输入一串字符,直到输入一个星号为止,统计输出其中的字母个数和数字字符个数

/>            string ss = 

是一段字符吧,一个怎么统计其中的个数啊?

Ingeneral,whenyouinputcypheragain,asteriskswillreplacecharacterssothathavenotothersbeinformedofthecy

classProgram//该程序不完整,你只需少加修改{staticintnum=0;staticvoidMain(string[]args){Console.WriteLine("请输入一串字符：

int main(){long n,i,j,s,k;cin >> n;for (i=1;i<=n;i++){for&nb

#include"stdio.h"intmain(void){intrepeat,ri;inti,j,n;scanf("%d",&repeat);for(ri=1;ri

itdoesnotchecktheinputofothercharactersexceptnumber.

有问题,加入这个群151988677找千里#include#definemax100voidjiancha(intcount[],charstring[]){inti=0;while(string[i

n-englishwords,pleaseenterenglishwords.字符word可以用characters代替

yoursurnamecontainsnon-englishwords,pleaseenterenglishwords.字符word可以用characters代替

什么语言你都没有说原理其实很简单属于简单的条件循环结构而且条件就是输入的值是否与预定的数字相等.

#includeintmain(void){inti,j,a;charc('y');do{do{couta;cout

#include#includeintmain(){charwords[10][7]={"zero","one","two","three","four","five","six","serven",

importjava.io.*;/***输入整数n,输出由n行n列星号字符组成的三角形图案**@authoruser**/publicclassXing2{publicstaticvoidmain(S

程序很简单,仔细看吧：vara:array['0'..'9']oflongint;b:array['0'..'9']ofchar;c,i,j,tt:char;t:longint;begin//初始化f

&&这是测试过的程序,请你再测试.&&1.CLEARSETTALKOFFS=0DOWHILE.T.ACCEPT"输入一串数字字符："TOXM=LEN(x)IFM=10exitENDIFloopENDD

Fieldsarenotmarkedwithanasterisknexttotheinputbox,doesnotneedtoinputcharacters

#include#includeintmain(){chars[10]="ABCDE";printf("请输入一个字符和一个数字,以逗号分隔:");inta;charb;scanf("%c,%d",&

programdaihuan;vars,e,tmp:string;i,j,k,l:integer;t:char;procedureswap(t:char);begincasetof'a':tm

#include <stdio.h>　　char* upper2lower(char *s)　　{　　char *p=s;　　while(*p)