调用函数,求1! 2! 3! ...... 10!

您的程序有多处错误.既然是初学,就先把最基本的东西都弄清楚啊,否则别人都不愿意帮您.简单列出您的错误如下：1）在max函数内又声明了a[10],这和传递给max函数的参数同名.2）在max函数内声明了

whilesqrt((b(:,k)-a(:,k))'*(b(:,k)-a(:,k)))>=apxlFLK=fun(lbt(:,k));%%%%%调用函数funFMK=fun(mu(:,k));%%%%

n=1:63;x=2.^n;sum2=sum(x)得到结果:sum2=1.8447e+019

第一题：两个TextBox,一个Command.OptionExplicitPrivateFunctionMaxModNum_(ByValaAsLong,ByValbAsLong)_AsLongDim

#include <stdio.h>float sum1(int n);float sum2(int n);void main(

用递归函数#include#includeintinv(intx);main(){intsum=0,i;for(i=1;i

#includefloatadd(floatx,floaty);floatsub(floatx,floaty);floatmul(floatx,floaty);floatprocess(floatx,

intjie_cheng(intn){if(n==1)return1;returnn*jie_cheng(n-1);}doublefact(intn){doublesum=0;for(inti=1;i

#include#includedoublefun1(doublen){doublesum=0;doublem=0;for(inti=2;inum;if(num%2==0){cout

varpp=0,kk=0functionf1(x){pp=x*xreturn(pp)}functionf2(y){kk+=yreturn(kk)}for(vari=1;i

sum(n){intsum,i;if(i=1;i

vars,ans:int64;i:longint;beginreadln(s);fori:=1tosdoinc(ans,facto(i));writeln(ans);end.也许需要高精度!当s>=1

/>#includeusingnamespacestd;longunsignedfun(intn){if(n>1)returnn*fun(n-1);return1;}voidmain(){intn;c

#include<stdio.h>int calc(int n){\x09int i,sum;\x09i=1,sum=0;\x09while(i<=n)

#includeintfact(int);main(){inti,sum=0;for(i=1;i

#includemain(){longintn,i,j,k;doublem;printf("请输入数字'n':");scanf("%d",&n);if(n%2==1){for（i=0;i0){for（

#includelongfac(intn){longz;if(n==1)z=1;elsez=n*fac(n-1);returnz;}intmain(){inti,n;longsn=0;scanf("%

什么事指针函数?不知道这个但是完成上面的题貌似很简单

#includeusingnamespacestd;longunsignedfun(intn){if(n>1)returnn*fun(n-1);return1;}voidmain(){intn;cou

递归函数如下：首先斐波拉楔数列的前n项和递推公式为S（n）=S（n-1）+S（n-2）+1；(根据通项公式a[n]=a[n-1]+a[n-2]很容易推导出来)递归函数如下所示;intsum_Fibon