计算题24除以4=2x( )-搜答案-神马作文网

x^2-x+(1/4)=x^2-2*x*(1/2)+(1/2)^2=(x-1/2)^2

计算题x÷2=3x-126

x÷2=3x-126x=6x-2525x=252x=50.4

(1/3)*(x+2)^3+C

两边乘以(x-2)(x+2)得x(x+2)-(x+2)(x-2)=-2x²+2x-x²+4=-22x=-6x=-3检验：x=-3是方程的解∴方程的解是x=-32、原式=-x(x-y

24除7除以6除49再答：错了是7除24再答：的答案除以6除49的答案

(4x^2-y^2)^2可化简为（2x+y)^2*(2x-y)^2(-2x+y分之4x^2-4xy+y^2)^3可化简为{-2x+y分之（2x-y)^2}^3简化为{-（2x-y）}^3然后相除得到-

5x-10+8=4-6+2x5x-2=(-2)+2x3x=0x=0就是0解啊,你看看题目有没看错,不然就是答案错了

皇甫邵贤,你好：2/3＋5÷2/3－2/3＝2/3－2/3＋5÷2/3＝5×3/2＝15/2

(0.25x²-x+1)÷(1-0.5x)=(1-0.5x)²/(1-0.5x)=1-0.5x

你的题目似乎最后应是……除以2012分之2013吧?如果是这样的话,答案应是2013.即从左到右,把除法转化为乘法,即可约分.再问：没有看错，过程再答：原式=1/2*2/3*3/4*4/5*……*20

[(a+1)(a+2)/(a^2-4a+4)-a/(a^2-2a)]/[a/(a-2)]=[(a+1)(a+2)/(a-2)^2-a/a(a-2)]/[a/(a-2)]=[(a+1)(a+2)/(a-

原式=[(x²+x-12)/(2-x-x²)]²×[(x²-3x+2)/(x²+5x+4)]²÷[(x²-5x+6)/(x

计算题7x(2-x)=3(x-2)

7x(2-x)=3(x-2)14x-7x²=3x-67x²+(3-14)x-6=07x²-11x-6=0(7x+3)(x-2)=0x1=-3/7x2=2

原式=(x+1)(x-1)/(x+2)²*1/(x+1)*(x+1)(x+2)/(x-1)=(x-1)/(x+2)²*(x+1)(x+2)/(x-1)=(x+1)/(x+2)

1/5*(x-1)=41/5x-1/5=41/5x=22/5x=22(x+23/6)/(4/3)=63/10(x+23/6)*4/3=63/104/3x+46/9=63/104/3x=107/90x=

这种题目只要分母没有根号就可以得出结果解法如下:(2√2+4)/(3+4√2)上下同乘以(3-4√2)得:((2√2+4)(3-4√2))/((3+4√2)(3-4√2))即有(6√2-16+12-1

原式=(x-y)^3*(y-x)^4/(y-x)^3/(x-y)=(x-y)^7/(x-y)^3/(x-y)=(x-y)^4/(x-y)=(x-y)^3

x:6/5=25/4:22x=(6/5)*(25/4)2x=15/2得x=15/4如还不明白,请继续追问.手机提问的朋友在客户端右上角评价点【满意】即可.

1除以x(x+1)+1除以(x+1)(x+2)+1除以(x+2)(x+3)+……+1除以(x+2012)(x+2013)=1/x-1/(x+1)+1/(x+1)-1/(x+2)+1/(x+2)-1/(

(-4x^2)(3x+1)=-4x^2*3x-4x^2*1=-12x^3-4x^2