计算:2a+2 a-1÷(a+1)-a²-1 a²-2a+1
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/22 21:35:14
a+a-2分之3-1=(a+b)-(2分之3+1)=2a-2分之5
(-2a)×(1/4a^3)=[(-2)×1/4]×(a×a^3)=-1/2a^4
{[(a-2)/a(a+2)]-[(2a-1)/(a-2)(a+2)]}÷(a+2)(a-1)/(a+2)^2先分解因式,再约掉(a+2)这个公因式=[(a-2)/a-(2a-1)/(a-2)]÷(a
(1)原式=a+2a(a−2)•(a−2)2a+2=a−2a;(2)原式=2x(x+2)−x(x−2)(x−2)(x+2)•(x+2)(x−2)x=x(x+3)(x+2)(x−2)•(x+2)(x−2
a³*1/a²=a³/a²=a
(a+1)(a+2)(a-3)=(a²+2a+a+2)(a-3)=(a²+3a+2)(a-3)=a三次方-3a²+3a²-9a+2a-6=a三次方-7a-6互相
列项,1/a(a+1)+1/(a+1)(a+2)+...+1/(a+2007)(a+2008)=1/a-1/(a+1)+1/(a+1)-1/(a+2)..-1/(a+2008)=1/a-1/(a+20
是a³/(a-1)-a²-a-1吧?==+已知:a³-1=(a-1)(a²+a+1)则:a³/(a-1)=(a³-1)/(a-1)+1/(a
{a×【a加5】}分之2再问:能否写下过程?谢谢了
(a+2/a²-2a-a-1/a²-4a+4)÷a-4/a=[(a+2)/a(a-2)-(a-1)/(a-2)²]×a/(a-4)=(a-4)/a(a-2)²×
【(A+2)/(A²-2A)-(A-1)/(A²-4A+4)】×(A-2)/A÷(4-A)/A²=【(A+2)/A(A-2)-(A-1)/(A-2)²】×(A-
裂项:1/a(a+1)=1/a-1/(a+1)1/a(a+1)+1/(a+1)(a+2)+...+1/(a+2006)(a+2007)=1/a-1/(a+1)+1/(a+1)-1/(a+2)+...+
2(a/a+1)^2再问:过程能发下吗
再问:第二步我算的是a(a+2)(a+5)分之2a-8呢....好吧我去重算....
(a+1)(a+2)(a+3)(a-6)=[(a+1)(a-6)][(a+2)(a+3)]=(a²-5a-6)(a²+5a+6)=(a²)²-(5a+6)
a^2/(1+a)+1-a=a^2/(1+a)+(1-a)(1+a)/(1+a)=a^2/(1+a)+(1-a^2)/(1+a)=(a^2+1-a^2)/(1+a)=1/(1-a)再问:不对,答案是1
2a(a-3)^1-6a^2(3-a)-8a(a-3)=2a(a-3)+6a^2(a-3)-8a(a-3)=2a(a-3)(1+3a-4)=2a(a-3)(3a-3)=6a(a-3)(a-1)----
=2a三次方+a