神马作文网计算:(4x²-y²)÷(2x y)
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/11 10:07:26
等于1/X*（X-Y）
-x^y^7+y^8)(这里有问题,x的几次方?再问：就是一次方再答：(x^8-x^7y+x^5y^3-x^4y^4+x^3y^5-xy^7+y^8)(x^2+xy+y^2)=（x^8-x^7y+x^
（1）x/（x+y)-x/(x-y)=x(x-y)/(x+y)(x-y)-x(x+y)/(x+y)(x-y)=(x^2-xy-x^2-xy)/(x+y)(x-y)=-2xy/(x+y)(x-y)（2）
4xy-(x+y)^2/xy(x+y)(x-y)÷x^2+xy-2y^2/x^2y+2xy^2=(4xy-x²-2xy-y²)/[xy(x+y)(x-y)]÷[(x-y)(x+2y
(x-3y)(y+2x)-(4y-3x)(3x+4y)=2x^2-3y^2-5xy+9x^2-16y^2=11x^2-5xy-19y^2
(4x²y--9y)/(2x+3)=y(2x+3)(2x-3)/(2x+3)=y(2x-3)
(-x-2y)*(3x-y)=-3x^2-5xy+2y^2
原式=3x-4y+(2y+x)-(x-3y)-6x=-3x-4y+(2y+x)-(x-3y)=-3x-4y+2y+x-x+3y=-3x+y
[12(x+y)³(y-x)]³÷[4(x+y)²（x-y)]²=【12×12×12÷(4×4)(x+y)^9(y-x)^3】÷【(x+y)^4(x-y)^2】
16(x+y)^8/9(x-y)^8=16/9*[(x+y)/(x-y)]^8哪个好理解用哪个.再问：有过程没。。。再答：这个过程其实没什么好研究的。。。[3(x-y)^2(x+y)^-2/4(x+y
原式=(2x²+8xy-3xy-12y²)-(3x²-6xy+xy-2y²)=2x²+8xy-3xy-12y²-3x²+6xy-x
(1)(-2x)^3-3x乘（x-2x^2）=-8x³-3x²+6x³=-2x³-3x²=-x²(2x+3)(2)[(x+2y)^2-(x-
(2x+y)(x-3y)=2x(x-3y)+y(x-3y);y(x-3y)+y(x+3y)=2xy;所以2x(x-3y)+2xy=2x(x-3y+y)=2x(x-2y);2x(x-2y)÷(2x)=x
4（x+y）^5（x-y）^4÷[2（x+y）³*（y-x）²]=4（x+y）^5（x-y）^4÷2（x+y）³÷（y-x）²=4÷2×(x+y)^5÷(x+y
(x-2y)^2-4(2x+y)(y-2x)+4x(y-2)=x^2-4xy+4y^2-4(y^2-4x^2)+4xy-8x=x^2-4xy+4y^2-4y^2+16x^2+4xy-8x=17x^2-
原式=(3x+y+3x-y)(3x+y-3x+y)÷2(2x-y)=12xy÷2(2x-y)=6xy/(2x-y)
(2X-4Y)(2Y+X)=2(X-2Y)(x+2Y)（把2提出来）=2x²-8y²不懂可以追问哦,望采纳,谢谢
(x-y)^7÷(y-x)^6+(-x-y)^3÷(x+y)^2=(x-y)^7÷(x-y)^6+[-(x+y)^3]÷(x+y)^2=(x-y)+[-(x+y)]=x-y-x-y=-2y
3x-2y-[-4x+(z+3y)]=3x-2y-(-4x+z+3y)=3x-2y+4x-z-3y=7x-5y-z
=12x^2-3xy+6x+4xy-y^2+2y-8x+2y-4=12x^2-y^2+xy-2x+4y-4