计算4x-3y-[-5x (2x y)]
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(1)=(x-y)(x+1)(x-1)(2)=x(x^2+x+1/4x)=x(x+1/2)^2(3)=4x^2+4xy+y^2-x^2+4xy-4y^2=3x^2+8xy-3y^2=(3x-y)(x+
两个式子作差得到x=5带入得到y=23
-x^y^7+y^8)(这里有问题,x的几次方?再问:就是一次方再答:(x^8-x^7y+x^5y^3-x^4y^4+x^3y^5-xy^7+y^8)(x^2+xy+y^2)=(x^8-x^7y+x^
X(11Y-2X)
(x-3y)(y+2x)-(4y-3x)(3x+4y)=2x^2-3y^2-5xy+9x^2-16y^2=11x^2-5xy-19y^2
(x+y)(x+y)^2(-x-y)^3=-(x+y)^6
原式=(x''+9xy+20y'')(x''-y'')带入数据得:(64/9-72/7+180/49)*(64/9-9/49)再通分=((3136-4536+1260)/441)*(3136-81)/
(4x²y--9y)/(2x+3)=y(2x+3)(2x-3)/(2x+3)=y(2x-3)
-(4y-3x)(4y+3x)(x+3)²-中间是乘吗?我感觉加更合理呢再问:不是第一题是(2x-3y)²-(4y-3x)(4y+3x)第二题是(x+3)²-2(x+5)
(-x-2y)*(3x-y)=-3x^2-5xy+2y^2
原式=3x-4y+(2y+x)-(x-3y)-6x=-3x-4y+(2y+x)-(x-3y)=-3x-4y+2y+x-x+3y=-3x+y
16(x+y)^8/9(x-y)^8=16/9*[(x+y)/(x-y)]^8哪个好理解用哪个.再问:有过程没。。。再答:这个过程其实没什么好研究的。。。[3(x-y)^2(x+y)^-2/4(x+y
原式=(2x²+8xy-3xy-12y²)-(3x²-6xy+xy-2y²)=2x²+8xy-3xy-12y²-3x²+6xy-x
=((x+y)-(x-y))*((x+y)-3(x-y))=2y*(4y-2x)=4y*(2y-x)带入得到=4*-0.8*(-1.6-5)=4*0.8*6.6=21.12
解代数式得:-3x的平方y-2y的三次方因为1/2的平方=-1/2的平方,所以结果仍正确给分吧!嘿嘿!
(x+4)·(-2x)-(x+1)(x-1)+(-3x+2)(x+1)=-2x²-8x-(x²-1)+(-3x²-x+2)=-2x²-8x-x²+1-
答:(x+y)^2×(-x-y)^3×[-3/4(x-y)^3]×5/6(y-x)^2=[(x+y)^2]×[-(x+y)^3]×(-3/4)×[(x-y)^3]×(5/6)×(x-y)^2=-1×(
原式=9x2-6xy+y2-4x2-4xy-y2+5xy-5x2=(9x2-4x2-5x2)+(-6xy-4xy+5xy)+(y2-y2)=-5xy.
3x-2y-[-4x+(z+3y)]=3x-2y-(-4x+z+3y)=3x-2y+4x-z-3y=7x-5y-z
=12x^2-3xy+6x+4xy-y^2+2y-8x+2y-4=12x^2-y^2+xy-2x+4y-4