解方程[4x+1]=3x- ,其中[a]表示不超过a的最大整数.
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6^x+4^x=9^x3^x*2^x+(2^x)^2=(3^x)^2,两边同除以(2^x)^2,(3/2)^x+1=[(3/2)^x]^2,设(3/2)^x=t,t+1=t^2,t^2-t-1=0,t
3/4X+6一1/4X=120一X乘以4得3x+24-x=480-4x3x-x+4x=480-246x=456x=76
(x+1)(x+3)+4x=-13x方+4x+3+4x+13=0x方+8x+16=0(x+4)方=0x1=x2=-4
解x(6-x)-2x(x+1)-(x³-3x^4)/x²=46x-x²-2x²-2x-(x-3x²)=44x-3x²-x+3x²=
2x²-3x+2x²-2x=4x²-8x+9-5x=-8x+93x=9x=3
4/3x=20x=15
4/(x-2)+(x-1)/[(x-2)(x-3)]-2/(x-3)=0[4(x-3)+(x-1)-2(x-2)]/[(x-2)(x-3)]=03(x-3)/[(x-2)(x-3)]=0不知道解了~~
x(2x-4)+3x(x-1)=5x(x-3)+82x²-4x+3x²-3x=5x²-15x+88x=8x=1
题目应该是(x-1)(x-2)(x-3)(x-4)=24,不然解不了[(x-1)(x-4)][(x-2)(x-3)]=24[x^2-5x+4][x^2-5x+6]=24设x^2-5x+5=y所以(y-
3x²-1=4x3x²-4x-1=0x²-4/3x-1/3=0x²-4/3x+4/9-4/9-1/3=0(x-2/3)²=7/9x=(√7+2)/3或
(x-3)(x-2)-(x-4)(x-1))/((x-1)(x-2))=((x-5)(x-4)-(x-6)(x-3))/((x-3)(x-4))2/((x-1)(x-2))=2/((x-3)(x-4)
6x²-9x-4x+2x²=-2x+8x²-11-9x-4x﹢2x=-11-11x=-11x=1
2x+4x+6x...+100x=1-(x+3x+5x+...+99x)x(2+4+6+...+100)=1-x(1+3+5+...99)x(2+4+6+...+100)+x(1+3+5+...+99
2/x^2+x+3/x^2-x-4/x^2-1=0(2/x^2+3/x^2-4/x^2)+x-x-1=01/x^2-1=01/x^2=1x^2=1x=1或-1
x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)x/(x-2)=2x/(x-3)+(1-x)/(x-2)(x-3)x(x-3)/(x-2)(x-3)=2x(x-2)/(x-2)(x-3)
方程的两边同乘x,得x|x|-4=3|x|,当x≥0时,x2-3x-4=0解得x=-1或4.∴x=4,当x<0时,x2-3x+4=0此方程无解,检验:把x=4代入x=4≠0.∴原方程的解为:x=4.
X^2+4X=60X^2+4X+2^2=60+2^2(X+2)^2=64X+2=8X=6
首先由题意得x+1≠0,x+7≠0,x+5≠0,x+3≠0,即x≠-1,x≠-7,x≠-5,x≠-3,则先简化方程(x+1+1)/(x+1)+(x+7+1)/(x+7)=(x+5+1)/(x+5)+(
(1/x-7)+(1/x-1)=(1/x-6)+(1/x-2)1/(X-7)-1/(X-6)=1/(X-2)-1/(X-1)(X-6-X+7)/[(X-7)(X-6)]=(X-1-X+2)/[(X-1
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