若m^2-2m-1等于0，m=?-搜答案-神马作文网

2m(5m-3)+2m(1-5m)=24解这个方程就是了10m²-6m-10m²+2m=24-4m=24m=-6

因为m²+m-1=0所以m²=1-m所以m³+2m²+2009=m(1-m)+2m²+2009=m²+m+2009=1+2009=2010

x的次数是1所以2m+1=1m=0选A’

m*m-3m+1=0移项得m*m=3m-1可得m=3-1/m∴m+1/m=3两边平方,得m*m+1/m*m=9∵2m*m+2\m*m=2(m*m+1/m*m)代入,得2m*m+2\m*m=2×9=18

m^2+m-1=0所以m^2=1-mm^2+m=1这两个式子后面有用m^3+2m^2+2008=m^2*(m+2)+2008(第1个式子)=(1-m)(m+2)+2008=-m^2-m+2+2008=

2m^2-5m+1/m^2中把2m^2=m^2+m^2,移项后就是(m^2-5m)+m^2+1/m^2

错了,是m³+2m²+3m²+m=1原式=m³+m²+m²+3=m(m²+m)+m²+3=m+m²+3=1+3

m=-2

解m²-m-1=2m²-m=3m²-m+1/4=3+1/4(m-1/2)²=13/4开方得：m-1/2=√13/2或m-1/2=-√13/2∴m=1/2+√13

括号里面乘出来：M-M^3+M^3-2M+2012>=0,M-2M+2012>=0,得：M

m-1/m=-1m^2-1=-mm^2+m=12m^2+2m-1=1

m²-2m=1m²-2m+1=1+1(m-1)²=2m-1=±√2m1=1+√2,m2=1-√2

m^2+m-1=0m^2+m=1m^3+2m^2+1=m(m^2+m)+m^2+1=m+m^2+1=1+1=2

4024

3^2m*4^2m*36^m/72^2m=9^m*16^m*36^m/72^m*72^m=154^m*36^m/72^m*36^m*2^m=1^m=1楼上错了,知道吗?

因为m²+m-1=0--------所以,m²=1-m,m=1-m²---m³+2×m²+2009=m²*m+2×m²+2009=

2m-1=-3m+2 m等于?

1

m3-

m-1=±1,m≠2∴m=0

2{（m-1)m+m(m+1)}{(m-1)m-m(m+1)}.=2（m²-m+m²+m）(m²-m-m²-m)=2*2m²*(-2m)=-8m