编程计算:T=1-1 2 1 3-1 4 ....-搜答案-神马作文网

数学计算可以简化过程：因为1-2=-1,3-4=-1...所以得出-1+(-1)+...,重复(100/2)次,即代码为(这是最简单而且最快速的办法)：DimsAsInteger=-(100/2)如果

intn,sum=0;cin>>n;for(inti=1;i

clear&&清屏t=o&&给t赋初值s=1&&赋初值给sfori=1to10&&循环s=s*i&&s=i!t=s+t&&t为1到i的阶乘和endfor&&循环终点"T=1!+2!+3!+…+10!=

#includeintmain(){doublek=1,s=0,i;for(i=1;i

#includevoidmain(){inti,b=1,s=0;for(i=1;i

s=0sum=1;for(i=1;i

programjuio;vari:integer;a,s:real;begina:=0;fori:=1to100dobegins:=a+i;a:=s;end;writeln(s:0:0);readln

C

#includeintmain(){intk=1;doublesum=0;for(inti=1;i

i=0s=0DOWHILEi

#includevoidfun(long*num,intnn);intmain(){intn;longsum=0;cout再问：调试了好像有点问题再答：#includevoidfun(long*num

#include#includefloatf(floatx){doubley;if(x

PublicFunctions(n)Dimi,j,t,resFori=1Tont=1Forj=1Toit=t*jNextres=res+tNexts=resEndFunction

你好!PrivateSubForm_Click()DimiAsIntegerDimsAsIntegerFori=1To100s=s+iNextiPrintsEndSu

clearallcloseallx=1:1:20;lx=length(x);fork=1:1:lxs=0;s=s+factorial(x(k));end>>ss=2.4329e+018

#includeusingnamespacestd;intf(intn){ints=0,t=1;for(inti=1;i

1、clears=1fori=1to9s=s+i/(i+1)endfor2、clears=0fori=10to100ifmod(i,2)=0s=s+iendifendfo

看的出来你是在考试呢.呵呵intsum=0;for(inti=1;i再问：嘻嘻……再答：娶我吧~啦啦啦珍竹意坊你的最佳答案在这呢啦啦啦再问：好的……呵呵我都不知道选哪个好

DimaAsIntegerDimsAsIntegerPrivateSubCommand1_Click()s=0Fori=1To100IfiMod2=1Thena=iIfiMod2=0Thena=-is

#includeusingnamespacestd;intmain(intargc,char*argv[]){ints=0;inttemp=1;inti;for(i=1;i