编程计算1-100中能被3或能5整除的数的和(要求提交MATLAB程序文件)-搜答案-神马作文网

数学计算可以简化过程：因为1-2=-1,3-4=-1...所以得出-1+(-1)+...,重复(100/2)次,即代码为(这是最简单而且最快速的办法)：DimsAsInteger=-(100/2)如果

我简单写了一个应该符合你的要求：publicclasstests{publicstaticvoidmain(String[]args){intn=0;for(inti=0;i

#includemain(){intsum,i;for(i=1,i

voidmain(){intsum=0;//存储计算结果,初始为0for(inti=3;i{sum+=i;//累加}printf("theresultis%d",sum);//输出}

intmain(void){\x09intsum=0,i;\x09for(i=1;i

#include"stdio.h"intmain(){ doublesum=0; &

programjuio;vari:integer;a,s:real;begina:=0;fori:=1to100dobegins:=a+i;a:=s;end;writeln(s:0:0);readln

i=0s=0DOWHILEi

Sum=0Fori=100To300IfiMod21=0ThenSum=Sum+iEndIfNext==>优化一点：Sum=0Fori=100To300IfiMod21=0ThenSum=Sum+ii

intsum=0;for(inti=100;i

PrivateSubCommand1_Click()Dimi,j,sumAsIntegerFori=1To100j=iMod21Ifj=0Thensum=sum+i^2NextiPrintsum'打印

#include#includeintmain(){intsum=3,a=3,b;while(sum{b=a;if(a%3==0)a+=7-(a%7);elsea+=3-(a%3);sum+=a;}p

#includemain(){\x09inti,t,sum;\x09i=1;\x09sum=0;\x09for(t=1;t

PrivateSubCommand1_Click()Dimi,sAsIntegers=0Fori=1To100IfiMod3=0OriMod7=0Thens=s+1EndIfNextiPrintsEn

voidmain(){intsum=0;for(inti=2;i

你好!PrivateSubForm_Click()DimiAsIntegerDimsAsIntegerFori=1To100s=s+iNextiPrintsEndSu

1、clears=1fori=1to9s=s+i/(i+1)endfor2、clears=0fori=10to100ifmod(i,2)=0s=s+iendifendfo

DimaAsIntegerDimsAsIntegerPrivateSubCommand1_Click()s=0Fori=1To100IfiMod2=1Thena=iIfiMod2=0Thena=-is

publicclasslianxi2{publicstaticvoidmain(Stringagrs[]){intsum=0;intsum1=0;intsum2=0;inti=1;while(i