编写计算圆面积的Function过程
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importjava.io.BufferedReader;importjava.io.InputStreamReader;publicclasstest{publicstaticvoidmain(St
FunctionS(rAsSingle)AsSingle'Function过程Constpi=3.1415926535898S=pi*r^2EndFunctionPrivateSubForm_Clic
importjava.util.Scanner;publicclassTest{publicstaticvoidmain(Stringagrs[]){Scannera=newScanner(Syste
#includedoublecalRectArea(doubledWidth,doubledHeigh){returndWidth*dHeigh;}voidmain(){doublea,b,mul;s
输入三角形三边长,求三角形面积.#include“math.h”main(){floata,b,c,s,area;scanf(“%f,%f,%f”,&a,&b,&c);s=1.0/2*(a+b+c);
#include<stdio.h>double zc(double x, double y){ ret
public class Area {public static void main(String[] args)&
#include <stdio.h>#include <math.h>//double sin(double x);#define&nb
这个有啥疑问的?doubler;r=输入所得,就具体语言而定doublereult;doublepi=3.141592653;result=pi*r*r;
publicclassTest{publicstaticvoidmain(String[]args){System.out.println("圆的面积:"+area(2));System.out.pr
#include <stdio.h>float area(float r){ return 3.14159 *&nb
PrivateSubCommand1_Click()DimbjAsSingleDimzzAsSingleDimmjAsSinglebj=CSng(Text1.Text)Ifbj
#include#definepai3.15149256voidmain(){doubler,c,s;printf("pleaseinputr\n")scanf("%lf",&r);printf("c
#includevoidmain(){doubler,s,l;printf("请输入圆的半径\n");scanf("%lf",&r);s=3.14159*r*r;l=2*3.14159*r;print
先给个好评!再答:
privatefunctions(byvalrasdouble)asdoubles=PI*r*rendfunction
//使用海伦公式#include/*ForIO*/#include/*Forsqrt()*/intmain(void){doublea,b,c,p,s;printf("请输入a,b和c:");scan
C编程求助编写一个基于对象的程序:输入半径,计算圆的周长和面积并输出实现#include
clearinput"请输入圆的半径:"torl=2*pi()*rs=pi()*r*r?"周长是:",l?"面积是:",s
m=2a+2b;应该改成m=2*a+2*b;程序中2a,2b是不允许的,没有意义的.