编写程序计算100到1000中,有多少个整数其各位数字之和是7,并把它们输出
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#!/bin/bashforiin$(seq10)doecho$((i*i))doneexit0
#includemain(){doublex,y;scanf("%lf",&x);if(x
#includevoidmain(){intsum=0;for(inti=1;i
PublicSubqqqqq()DimiAsIntegerDimjAsIntegerDimsAsIntegerDimCAsBooleans=0Fori=2To100C=FalseForj=2Toi-1
#include#includeboolIsprime(intnum){if(num再问:亲、我复制粘贴进C++程序、显示有一个错误、麻烦你在修改下把、感谢了、给你追分~再答:没错啊!你把错误贴上来
x=[3,4,5,6,7,8,9,10];y=[4,5,6,7,8,9,10,11];z=21.89-9.87*x+8.09*y-7.98*x.*y-1.87*x.^2-7.98*y.^2z=1.0e
dimiaslongdimsumaslongsum=0fori=1to100step2sum=sum+inextiprintsum
doublef(doublex){doubles=.0;if(x
intsum=0;for(inti=0;i
PrivateSubCommand1_Click()DimsAsString,nAsInteger,iAsIntegerFori=1To100n=n+iNextiPrint"1+2+3+……+100=
functiongetR(a,b){vars=0;while(b>=a){s=b--+s;}returns;}document.write(getR(1,1000))
floatfun(intn){floatsum=0;inti;for(i=1;i
#include <stdio.h>int main(){ float x, tax = 0;
#include"stdio.h"voidmain(){intsum=0;intn=1,i;for(i=1;i
//分别计算1到1000之间所有3的倍数之和和所有7的倍数之和intmain(){intsumA=0;//3的倍数的和intsumB=0;//7的倍数的和for(inti=1;i
;MOVAX,AANDAX,B;AX=aANDbMOVBX,AXORBX,B;BX=aXORbADDAX,BXADDAX,BX;AX=2*(aXORb)+aANDbADDAX,A;AX=a+2*(aX
输出结果哪里不对可以说下不?再问:有发代码的图片,有看见么?如果看不见的话,请看私信……拜托了~再答:#include"stdio.h"#include"time.h"#include"stdlib.