编写程序,计算 s=6! 10! 22!
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inta,n;doublesum=0;scanf("%d%d",&a,&n);for(sum=a,i=2;i
;modelsmall.stack100h.data.codestart:MOVAX,0MOVCX,100;LABEL:ADDAX,CXDECCXLOOPLABEL;循环50次;AX=2+4+6+8+
s=0k=1whilei
实际上S=n(n+1)(2n+1)/6再问:那程序怎么写啊?再答:InputnS=n(n+1)(2n+1)/6PrintS
inti,j;\x09intn,sum=0;\x09inttemp=1;\x09scanf("%d",&n);\x09for(i=1;i
#includeintmain(void){intn=0,i=0;doublep=1,q=0,s=0;printf("n=");scanf("%d",&n);for(i=1;i
VB程序PrivateSubCommand1_Click()Dima,iAsIntegeri=1Whilei<50s=s+(i+1)/ii=i+1WendPrint"s=";sEndSu
#includeusingnamespacestd;voidjishu(intn){intk=1;inta=1;doubles=0;for(inti=0;i
inti,S=0;for(i=1;i
我用php语言写的.分两个步骤,一个是计算每个节点的值,用递归算法.一个是节点的累加,用循环算法.这么好的答案,不给分,没良心.再问:谢谢了,我没说清楚,我现在学的是c++语言,真的很感谢
希望能帮到你.#include"stdio.h"intmain(){inti,j,n,s,temp;printf("请输入n的值:");scanf("%d",&n);for(i=1;i
publicclassTest{publicstaticvoidmain(String[]args){ints=0;intn=1;for(inti=0;i
#includeusingnamespacestd;voidmain(){intn,t=0;longsum=0;cin>>n;for(inti=1;i
你好.代码如下:#include<stdio.h>#include<stdlib.h>intmain(intargc,char*argv[]){doubles=0.00;/*总
第一种:s=0i=1dowhilei
importjava.util.*;publicclassNumberTest{publicstaticvoidmain(Stringarg[]){inta=5;intb=6;intc=2;intS=
用什么语言啊?如果是java的话就如下:ints=0;for(inti=1;i
;MOVAX,AANDAX,B;AX=aANDbMOVBX,AXORBX,B;BX=aXORbADDAX,BXADDAX,BX;AX=2*(aXORb)+aANDbADDAX,A;AX=a+2*(aX
CLEARSETTALKOffs1=0forn=1to10s1=s1+jc(n)next"1!+2!+3!+.+10!=",s1FUNCTIONjcPARAMETERSis=1FORj=1TOis=s
#includeintmain(){inti,s=0;for(i=1;i