编写程序,已知有一个整数152,计算其每位数字的累加和.
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#includemain(){inta,b,c,d,max,min;scanf("%d,%d,%d,%d",&a,&b,&c,&d);max=a;min=a;if(b>max)max=b;if(c>m
+=functionadd(){varA=document.getElementById("a").value;varB=document.getElementById("b").value;varA
#includeintfun(intn){inti,j;for(i=2;i
#includeintmain(){intx;inta[20];scanf("%d",&x);inti;for(i=0;x>=10;i++){a[i]=x%10;x=x/10;}
#includeintgongyue(intm,intn){intr;if(m==n)returnm;elsewhile((r=m%n)!=0){m=n;n=r;}returnn;}voidmain(
#includeusingnamespacestd;boolpalindrome(char*str){\x09inth=strlen(str);\x09for(inti=0;i
//也不说用什么语言,我用C语言来实现!#include#includeintprime(intm){inti,n;if(m==1)return0;n=(int)sqrt((double)m);for
input(x)ifx
varn,i,min,max,maxi,mini,s:integer;x:array[1..100]ofinteger;ans:real;beginreadln(n);fori:=1tondoread
#include#includevoidmain(){intn,s,j,i;printf("inputn(n
我刚刚编的,可以.不知道是不是你所要的.#includevoidmain(){intn;printf("欢迎来到计算整数的三次方的程序!\n");printf("请输入您要计算的数:");scanf(
INPUTxa=xMOD2IFa=0THENPRINT"x是偶数"ELSEPRINT"x是奇数"ENDIFEND
pt = {2, 2};ContourPlot[ Sqrt[(x - pt[[1]])^2 + (y -&nb
#includeusingnamespacestd;voidmain(){intn;cin>>n;if(n%2==0)cout
//第1题#include#includeusingnamespacestd;intmain(){inta;cin>>a;cout
importjavax.swing.JOptionpane;//导入JOptionpane类.publicclassTest{publicstaticvoidmain(Stringargs[]){in
/>vart;varl=prompt('请输入边长',3.5);t=3.1415926*(l/2.0)*(l/2.0);document.write("边长:"+l);document.write("
importjava.applet.*;importjava.awt.*;importjava.awt.event.*;publicclassTest3_2extendsAppletimplement
ifxmod2=0thenmsgbox"是偶数"elsemsgbox"是奇数"
使用什么VB的话是INPUTNIFN\2=0THENPRINT'是'ELSEPRINT'否'ENDIFEND