编写函数fun,函数的功能是从1到m之间的偶数之积-搜答案-神马作文网

printf("f=%f\n\n",f);out=fopen("outfile.dat","w");

PrivateSubfun()ifimod2=0thenforx=itoastep2s=s*xnextxelseforx=(i+1)toastep2thens=s*xnextxendif试试看行不行吧

#includedoublefun(doubleh){returnfloor(h*100+0.5)/100;}

#include#includeintfun(intx){intr=1,d,c;while(1){d=x%10;r=r*d;x=(x-d)/10;if(x==0)break;}returnr;}mai

includeincludeddoublefun(inta,intb,intc){intp;p=(a+b+c)/2;returnsqrt(p*(p-a)*(p-b)*(p-c));}再问：ok再问：

int是整型long是长整型long的空间比int大int只能定义数-32767到32767大于这个范围用long定义按标准规定int的长度是16位或者32位,long是32位.大部分C++编译器中i

#include#includeintprime(inti){intk;for(k=2;k

#include#defineN10floatfun(intnum[N[N]){inti,j,k=0,sum=0;floataverage;//下面求数组周边元素的平均值for(i=0;i再问：顶角的

上面的错了应该是intfun(){inti,sum=1;for(i=1;i

#include#includevoidswap(intc[],intlen){inti=0;inttmp;for(;i{tmp=c[i];c[i]=c[len];c[len]=tmp;}}intmu

1,JAVA编的,n可以任意赋值publicdoublefun(intn){doublesum=0;for(inti=1;i1;n--){inti=max(a,n);inttemp=a[i];a[i]

#include <stdio.h>#include <stdlib.h>#include <math.h>double f

high是什么啊?数组还是整数啊?

Private Sub Command1_Click() Dim x As Single, y

Functionsum(n)AsDoublesum=0Fori=1TonIfiMod2=0Thensum=sum+i*iNextEndFunction

1.intf1=0,f2=1,f3;2.returnf3;继续写：f3=f1+f2;f2=f3;f1=f2;

#include#includedoublefun(intn)//计算1!+2!+3!+.+n!,并赋值给fun{inti;doubles=0,t=1;for(i=1;i

#include#includefloatfun(inta,intb){floatc;c=sqrt(a)+sqrt(b);returnc;}intmain(){inta=12,b=20;floatc;

intfun(intn){inti,m=1;for(i=1;i

这个题目应当有原来的程序,让人填空.如果自己写程序,很简单：#include#includevoidfun(int*x,int*y){intz;z=*x;*x=*y;*y=z;}main(){inta