编写一个程序计算两个非0的实数
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#includevoidmain(){inta,b;printf("Inputtwointegers:");scanf("%d%d",&a,&b);printf("和:a+b=%d\n",a+b);p
importjava.io.BufferedReader;importjava.io.InputStreamReader;publicclasstest{publicstaticvoidmain(St
用什么语言编写再问:c语言
//别说100位,1000位都没问题,给你个例子.#include#definePRECISION2800#defineFRACTION1000#defineGROUP4#defineINITIALV
PrivateSubCommand1_Click()Dima,xAsSinglea=Val(Text1.Text)Ifa再问:x=x+a*0.2+3000*0.2怎么都乘0.2呀?
#includeintgongyue(intm,intn){intr;if(m==n)returnm;elsewhile((r=m%n)!=0){m=n;n=r;}returnn;}voidmain(
#includeintmain(){intm,n;do{printf("输入两个非零整数:\n");scanf("%d%d",&m,&n);}while(m==0||n==0);printf("%d+
INPUT"a=",aINPUT"b=",bPRINT"|a|+|b|=";abs(a)+abs(b)#includeinta,b;scanf("%d",&a);scanf("%d",&b);prin
#includeintmain(){intm,n;do{printf("输入两个非零整数:\n");scanf("%d%d",&m,&n);}while(m==0||n==0);printf("%d+
maylab软件挺好编写的用c语言也不难
#includevoidmain(){floata,b,result;charc;printf("pleaseinputastatement:");scanf("%f%c%f",&a,&c,&b);s
voidGetGCMAndLCM(inta,intb,int*iGCM,int*iLCM){intiMin=a>b?b:a;intiMax=(ainti=1;intiMaxIndex=0;
我也刚学C,费了好几个小时,终于把这个问题搞定了!已经运行过了,结果跟谭版结果一样,敬请放心使用.#include"stdio.h"#include"math.h"voidmain(){doublea
#include <stdio.h>int main(){ float x, tax = 0;
doublefunction(intn){doublevalue=0;for(inti=1;i
#includeusingnamespacestd;intmain(){inta,b;cout
#includeintmain(){floata,b,s,m,n,j;scanf("%f",&a,b);s=a+b;m=a-b;n=a*b;j=a/b;printf("%f\n",s,m,n,j);r
#include"stdio.h"main(){inta,b;printf("请输入两个数");scanf("%d",&a);scanf("%d",&b);printf("a=%d,b=%d,a+b=
#includeusingnamespacestd;intmain(){floata,b,c,d,e,f;cin>>a;cin>>b;if(a!=0&&b!=0){c=a+b;d=a-b;e=a*b;
"计算两个给定的长方形的周长和面积"是两个长方形还是一个长方形..需要输入什么条件..如果是输入长,宽,然后计算面积的话..那么#include"stdio.h"voidmain(){floatcha