编写1到100之间偶数之和用main函数调用-搜答案-神马作文网

#includeintmain(){\x09intsum=0;\x09inti;\x09for(i=0;i再问：CtrlC+CtrlV啊有木有亲~再答：啥?我自己写的，不好意思改成for(i=50;i

Next循环SUM=0FORi=2TO100STEP2SUM=SUM+I;NEXTIwhile循环SUM=0i=2whilei

intjishuhe=0;intoushuhe=0;for(inti=1;i

参考下吧,不一定是最合适的：using namespace::std;#include<iostream>using namespace std;int&nb

#includevoidmain(){inti=0,j=0,k=0;for(i=1;i

i

#includevoidmain(){ints=0;for(inti=0;i

解法1:#includeintF1(){return50*(1+99)/2;}intF2(){return50*(2+100)/2;}voidmain(){printf("Oddnumbersum=%

clears=0fori=2to100step2s=s+iendfo

#include#includevoidswap(intc[],intlen){inti=0;inttmp;for(;i{tmp=c[i];c[i]=c[len];c[len]=tmp;}}intmu

#include"stdio.h"intmain(){intcountou,countji=0;inti=0;for(i=1;i

inti=2;do{if(i%2==0)/*各种不同的语言输出i,*/}while(i

把奇数的一起补上了#include"stdio.h"intmain(){inta=0,b=0;inti=0;for(i=0;i

declarev_countnumber:=1;v_sumnumber:=0;beginforv_countin1..100loopifmod(v_count,2)=0thenv_sum:=v_sum

要填空吗?但你的结果好像是错的,1+2+.+100=5050,但你的结果两个加起来只有5000啊(1)i

#include"stdio.h"intgetsum(inta,intb)//要声明a,b为int型{inti;intsum=0;for(a%2==0?i=a:i=a+1;sum=sum+i;i+=2

clears=0fori=0to5000step2ifi%5=0s=s+iendififs>500exitendifendfo

（一）#includeintmain(){inti=1;printf("1-100之间的偶数有：\n");for(;i

#include#includevoidmain(){inti,j,sum=0,s;for(i=3;i{s=sqrt((double)i);for(j=2;j{if(i%j==0)break;}if(

intfoo(){//只可能有奇inti=(7*13*5);//455intsum=0;while(i