log的三次方 81= .log三次方3
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此题缺少底数,你仔细看看,这运公式挺快的,假如底数是a的话,那么答案为(loga(x^3-1))`=3x^2/(x^3-1)*loga(e)再问:题目完整是这样的:d除以dxlog(x的三次方-1)再
log3(3/3)^(3/4)=log3(1)=0
log(36)45=lg36/lg45log(18)45/log(18)36=[lg(45)/lg(18)]/[lg(36)/lg(18)]=lg(45))/lg(18)*[lg(18)/lg(36)
一层层扒皮就好了log底数9[log底数3(log底数2真数x)]=0log底数3(log底数2真数x)=1log底数2真数x=3x=2^3=8所以x^(-1/3)=2^[3X(-1/3)]=2^(-
log8(9)=lg9/lg8=2lg3/(3lg2)=(2/3)log2(3)
∵log(a)(m/n)=log(a)(m)-log(a)(n)∴-loga1/x=-(loga1-logax)∵log(a)(1)=0∴-(loga1-logax)=logax明教为您解答,如若满意
y=log(2)2+log(2)x+3log(2)x-4=[4log(2)x]-3值域的话就是(-无穷,+无穷)[4log(2)x]-3=0x=2ˇ(3/4)
已知a的三次方=8/27(a>0),则log(3/2)a=log(3/2)³√(8/27)=log(3/2)2/3=-1;您好,很高兴为您解答,skyhunter002为您答疑解惑如果本题有
原式=log2748×1242−1=log22−12−1=−12−1=−32,故答案为−32.
log(a)(M^n)=nlog(a)(M)(n∈R)log(2)(3)^-3=-3log(2)(3)只能化简到这里
log[tana]cosa=log[tana](sina/tana)=log[tana]sina-1=1/log[sina]tana-1=1/log[sina](sina/cosa)-1=1/(1-l
(log(4)3+log(8)3)(log(3)2+log(9)2)=(lg3/lg4+lg3/lg8)(lg2/lg3+lg2/lg9)=(lg3/2lg2+lg3/3lg2)(lg2/lg3+lg
等于负一
LogFactory来自common-logging包.如果用LogFactory.getLog,你可以用任何实现了通用日志接口的日志记录器替换log4j,而程序不受影响.publicstaticLo
log₂log₃log₄X=0log₃log₄X=1log₄X=3X=64log₃log₄logS
log以2为底X的对数的导数为1/[x*ln(2)]x^3的导数为3x^2整个的导数就是3x^2+1/[x*ln(2)]
log(2)4·log(4)8·log(8)m=log(4)16lg4/lg2*lg8/lg4*lgm/lg8=2lgm/lg2=2log(2)m=2m=2平方=4
你确定你的题目对吗,要补充好我才能回答哦再问:再答:2log310=log3100log3100+log30.27=log3(100*0.27)=log327=3
当n>10时,01,因此(log3)^n<1<(logn)^3;