知道最小值.最大值和平均值怎么求标准差
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PrivateSubCommand1_Click()Dima(1To20)Dimmax,ave,min,summax=0min=300Print"产生的20个数为:";Fori=1To20a(i)=I
#includevoidmain(){inta[12];inta1;printf("请输入12个整数");printf("\n");for(inti=0;i
用Excel求解,假定10个数存放在A1:A10最大值=MAX(A1:A10)最小值=MIN(A1:A10)平均值=AVERAGE(A1:A10)
DimnMaxasInteger,nMinasInteger,nTmpasInteger,nJsqasIntegerDimdSumasDoubleRandomizenTmp=CInt(Rnd*100)
publicclassETest{publicstaticvoidmain(String[]args){int[]a=newint[20];intsum=0;for(inti=0;ia[i]=(int
zd=Int(Rnd()*51)+50zx=Int(Rnd()*51)+50Fori=1To19xd=Int(Rnd()*51)+50Ifxd>zdThenzd=xdIfxdNextiPrintzd,
dima,max,min,sum,averagesum=0max=20min=50fori=1to20a=(Rnd*50)+50sum=sum+aifamaxthenmax=aprintanextpr
s=0p=50q=100Fori=1To20a=Int(Rnd*51+50)Printa;ifa>=pthenp=aendififa
#includetemplatevoidswap(T&a,T&b){Ttmp;tmp=a;a=b;b=tmp;}voidmain(){floatsum,max,min;floata[10];inti,
同意jaxxcyh的意见!看在你不知道的份上,给你一个参考程序.vara:array[1..20]ofreal;n,m,b:real;i,j:integer;beginfori:=1to20dobeg
#include "stdio.h"int main(){ float a[10]={0};
voidf(inta[],intsize,int*min,int*max,int*avg){*min=a[0];*max=a[0];*avg=0;intsun=0;for(inti=0;i{if(*m
#includevoidmain(){inta[10];inti,sum=0,ave=0,max,min;printf("pleaseinput10number:\n");for(i=0;i再问:谢谢
dimarr,idimn_min,n_max,n_sum,n_avarr="1,2,3,4,5,6,7,8,9,10,11,12"arr=split(arr,",")n_min=clng(arr(0)
1.你用自己的方法将这N个数字分别用数组a(1)-a(n)表示2.求最大fori=1ton-1ifa(i)>a(i+1)thenmax=a(i)elsemax=a(i+1)endifnexti3.求最
#include#defineN10voidmain(void){inta[N]={21,5,54,1,654,3,56,87,546,6};inti;intmin;//最小值intmax;//最大值
cleardimensiona(3)cstr=""cstrmax=""cstrmin=""cstraverage=""fori=1to3accept"请输入第"+alltrim(str(i))+"个数
OptionExplicitPrivateSubCommand1_Click()ClsDimmArr%(1To20),Max%,Min%,sum%,i%Max=50Min=100Fori=1To20R
inti=1;intj=2;intk=3;intminNum=Math.Min(Math.Min(i,j),k);//最小值intmaxNum=Math.Max(Math.Max(i,j),k);//
分别用random(),max(),min(),avg()函数.