java求100之内的偶数之和和奇数之和

这样的数是：6,12,18,24,.96所以和=6+12+18+.+96=（6+96）×16÷2=816

store0tosume,sumofori=100to1000ifi%2=0sume=sume+i&&偶数累加elsesumo=sumo+i&&奇数累加endifnext"100~1000偶数累加和=

intoddSum=0;intevenSum=0;inti=1;while(i再问：用for语句求100以内的奇数之和、偶数之和，怎么写？

#includeintmain(){\x09intsum=0;\x09inti;\x09for(i=0;i再问：CtrlC+CtrlV啊有木有亲~再答：啥?我自己写的，不好意思改成for(i=50;i

0；X

sum1=0;>>sum2=0;>>fori=1:100if(mod(i,2)==1)sum1=sum1+i;elsesum2=sum2+i;endend>>[sum1sum2]ans=2500255

在100之内,随便取2个数（如：20,1）,然后组成一个数组如下[20,1,8,8,8,8,8,8,8,8],随即就ok了,绝对80%.不过这种题目太无耻了,典型的抽奖作弊.

settalkoffclearstore0tosumou,ou,sumji,jifori=1to100ifi%2==0sumou=sumou+iou=ou+1elsesumji=sumji+iji=j

publicclassdemo{/***@paramargs*/publicstaticvoidmain(String[]args){inta=0,b=0;for(inti=1;i

解法1:#includeintF1(){return50*(1+99)/2;}intF2(){return50*(2+100)/2;}voidmain(){printf("Oddnumbersum=%

给,已经编译运行确认：#include#includevoidmain(){intsum=0,i;for(i=0;i

publicstaticvoidmain(String[]args){intarray[]=newint[20];intresult=0;Listlist=newArrayList();System.

publicclassSumOfEven{\x09publicstaticvoidmain(String[]args){\x09\x09intsum=0;\x09\x09for(inti=1;i

publicclassComputeOddEven{publicstaticvoidmain(String[]args){intsumOdd=0;//求奇数和的变量intsumEven=0;//求偶数

publicclassqiuhe{publicstaticvoidmain(String[]args){intsum1=0;intsum2=0;for(inti=1;i

把奇数的一起补上了#include"stdio.h"intmain(){inta=0,b=0;inti=0;for(i=0;i

简单数学方法：publicstaticvoidmain(Stringargs[]){intx=(202+300)*50/2;System.out.println(x);}for循环：publicsta

packagetest;publicclassTest{publicstaticvoidmain(Stringargs[]){System.out.println(getSum(123));}publ

if(!isPrime(j)||!isPrime(i-j)||j>=i)continue;如果i或j都不是素数,或者j>i,则继续循环搜索,否则,i和j就是要找的素数.

importjava.uti.Scanner;publicclasstest{publicstaticvoidmain(String[]args){Scannerscanner=newScanner(