直线x 2y-5 根号5=0被圆x平方 y平方-2x-4y=0截得的弦长为
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/20 22:31:22
x2y+xy2-x-y=xy(x+y)-(x+y)=(x+y)(xy-1)∵x+y=-5,xy=7,∴原式=-5×(7-1)=-30.
最简二次根式的是根号5(a²-b²)根号x²+y²,
首先,与直线2x+y=0相距√5/5的直线必然与直线2x+y=0平行,可设为直线2x+y+c=0,再根据平行线间距离公式d=|C1-C2|/√(A²+B²)知所求直线的参数c满足|
根据两直线间距离公式:d=|C1-C2|/√(A²+B²)|C1-C2|/√(A²+B²)=√5|3-C2|/√(1²+2²)=√5|3-C
5x2y+(-6x2y)+34x2y=14x2y答:和是-14x2y.
原式=2x2y+2xy-3x2y-3xy-4x2y=-5x2y-xy当x=-2,y=12时,原式=-9.
原式=(4x2y+5xy2+3x-2y+5)-2(2x2y-3xy2-2x+1)=4x2y+5xy2+3x-2y+5-4x2y+6xy2+4x-2=11xy2+7x-2y+3.
解;x+根号5=y-根号5=2分之根号2t所以,该直线方程为y=x+2根号5再问:x+���5=y-���5=2��֮���2t,û�������ܾ������һ���
解-x²y-xy²=-xy(x+y)=-2×5=-10
化简得:9-12Y^2+6Y+4+12Y^2+4Y-10-10Y+X-Y+1=X-Y+4带入X、Y值得:=3
是不是求:5x²y-[2x²-(3xy-xy²)-3x²]-2xy²-y²再问:是再答:已知是不是(x+3)²+|x+y+10|=
原式=x4+x3y+4x3y+x2y+4x2y2+4x2y2+xy2+4xy3+xy3+y4,=x3(x+y)+4x2y(x+y)+xy(x+y)+4xy2(x+y)+y3(x+y),=-x3-4x2
根号3x-y+5=0y=根号3x+5斜率K=根号3斜率角A=60
答案:2x^2y+2xy^2原式=4x2y-{x2y-[3xy2-2x2y+4xy2+x2y]}-5xy2=4x2y-{x2y-[7xy2-x2y]}-5xy2=4x2y-{x2y-7xy+x2y]}
∵x+y=5,xy=6,∴x2y+xy2=xy(x+y)=5×6=30.故答案为:30.
原式=5xy2-2x2y+3xy2-2x2y=8xy2-4x2y,∵(x-2)2+|y+1|=0,∴x-2=0,y+1=0,即x=2,y=-1,则原式=16+16=32.
代入x=-1,y=1,2x^y-(5xy^-3x^y)-x^=2*(-1)^*1-{5*(-1)*1^-3*(-1)^*1}-(-1)^=2-(-5-3)-1=9备注:2^表示2的平方
5x2y+3x2y+(-4x2y)=(5+3-4)x2y=4x2y,故答案为:4x2y.
由题意得:3C=A+B=8x2y-6xy2-3xy+7xy2-2xy+5x2y=13x2y+xy2-5xy,∴C=13x2y+xy2−5xy3,故:C-A=13x2y+xy2−5xy3-(8x2y-6
∵x+2y=5,xy=1,∴2x2y+4xy2=2xy(x+2y)=2×1×5=10,故答案为:10.