用递归的方法编写一个返回值是长整型的函数求fibonacci级数的前20项
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#includeintdigit(intn,intk){returnk>1digit(n/10,k-1):n%10;}intmain(){printf("%d",digit(12345,3));}
#includeunsignedintFibonacci(intn);intmain(void){inti;for(i=1;i
添加一个文本框输入前N项的N值,再添加一个命令按钮即可PrivateFunctionF(NAsLong)AsLongIfN>2ThenF=F(N-1)+F(N-2)ElseF=1EndIfEndFun
帮你写好了.unsigned int fib(unsigned int n) {\x09if (n == 1
PrivateFunctionF(nAsLong)AsLongIfn>2ThenF=F(n-1)+F(n-2)ElseF=1EndIfEndFunctionPrivateSubCommand1_Cli
#includelongintf(intn){if(n==0)return0;elseif(n==1)return1;elsereturnf(n-1)+f(n-2);}intmain
c:intfib(intn){return(n
// C++int F(int n) {if (n == 0) return 1;else if
longadd(intn){intt=n-1;if(t>1){longresult=n*t;longsum=result+add(t);returnsum;}else{returnn;}}楼上的方法,
cludestdio.hvoidmain(){intmax_4(inta,intb,intc,intd);inta,b,c,d,max;printf("Pleaseenterintergernumbe
#includeintFibonacci(intn){if(n==1||n==2)//递归结束的条件,求前两项return1;elsereturnFibonacci(n-1)+Fibonacci(n-
代码如下:OptionExplicitPrivateSubCommand1_Click()MsgBoxP(2,2)EndSubFunctionP(ByValnAsInteger,ByValxAsDou
longfac(int);这一步应该为longfac(int,float);y=fac(n);这一步应该为:y=fac(n,x);elseif(n=0)f=1;这一步应该为:elseif(n==0)f
#include <stdio.h>char* dg(char* instr, char* outstr, char* 
#includelongfib(intn){inta;if(n==1)a=1;elseif(n==2)a=1;elsea=fib(n-1)+fib(n-2);returna;}voidmain(){\
#include#includefloatmyfunction(intn,intx){if(0==n){return1;}elseif(1==n){returnx;}else{return((2*n-
functiongqj=erfen(p,a,b,e)ifabs(b-a)
1.#include"stdio.h"//#defineRECURSION1#ifdefRECURSIONlongfact(intn){if(n
#includeintfibo(intn){if(nreturn1;elsereturnfibo(n-1)+fibo(n-2);}intmain(){intn;scanf("%d",&n);print
//fibonacci数列:11235813213455...#includedoublefib_val[100]={0};doublefibonacci_1(intn)//递归,计算时间长,n最好不