用指针完成编程,输入3个数a,b,c,按大小顺序输出

测试通过,基本满足你题目要求,写得不太好importjava.util.*;importjava.util.regex.*;publicclasst10{publicstaticvoidmain(St

#includevoidmain(){inta[10],i,count1=0,count2=0,sum1=0,sum2=0;floataverage1,average2;for(i=0;i

#include"stdio.h"#include"conio.h"swap(int*p1,int*p2)/*放在前面,不然要声明*/{/*你原来定义的int*p1,*p2;放在函数形参里面*/int

下面这句有错：for(i=0;i

#include <stdio.h>#include <malloc.h>#define N 10int main( 

首先,swap()函数里得形参应为指向整型指针而且没有返回值,即定义为voidswap(int*,int*)其次,swap()函数中,两指针交换地址是借助intp;p=*x;*x=*y;*y=p;三是

#include#includevoidmain(){charsen[256];intben=0,men=0,spa=0,num=0,oth=0;inti;gets(sen);for(i=0;i='A

#includevoidmain(){charline[30];inti,count1=0,count2=0,count3=0,count4=0;printf("\n请输入一行字符:");gets(l

clsinput"diyigeshu=";ainput"diergeshu=";binput"disangeshu=";c以上语句是输入三个数max=-999ifa>maxthenmax=aifb>m

dimA(1to26)asintegerdimiasinteger,jasinteger,casstring*1,tasintegert=len(text1)fori=1totc=ucase(mid(

#includevoidmain(){charc;intletter=0;printf("请输入一行字符:\n");while((c=getchar())!='\n'){if(c>='a'&&c='A

#include#include#defineLENGTH20voidmain(){int*pBuff=(int*)malloc(sizeof(int)*LENGTH);inti,max,min;fo

问题是什么?

char*s[12]={"Jan.","Feb.","Mar.","Apr.","May.","Jun.","Jul.","Aug.","Sep.","Oct.","Nov.","Dec."};int

#include <stdio.h>#include <stdlib.h>int main(){  char *a[

a=XXb=YYc=MMifa>bthenmax=aelsemax=bendififc>maxthenmax=cendif

#include<stdio.h>main(){inti=0;intm=0;intn=0;charc;clrscr();while((c=getchar())!='\n'){if(65&l

#includevoidmain(){intc1=0,c2=0,c3=0,a[10],*p;printf("输入10个整数\n");for(p=a;p0)c1++;elseif(*p

#includeusingnamespacestd;intmain(){inta[100],s=0,n;inti;coutn;cout

有时间和空间要求么?简单方法如下：count=0;for(i=A;i再问：你的好像不行，这是我写的，看看怎么改一下#include#includeintmain(void){intA,B,count=