用java写出从键盘输入一个4位数,把每位上的数字求和后输出

importjava.io.*;importjava.util.*;classMain{publicstaticintgcd(intm,intn){while(true){if((m=m%n)==0)

packagetest1;importjava.util.Scanner;publicclassTest6{publicstaticvoidmain(String[]args){Scannerinpu

importjava.util.Scanner;publicclassSum{publicstaticvoidmain(String[]args){Scanners=newScanner(System

publicstaticvoidprintNum(intn){for(inti=2;ij){if(i%j==0){m++;}}else{break;}}if(m<1){System.out.print

importjava.util.Arrays;importjava.util.Scanner;publicclassDataCompare{\x09publicstaticvoidmain(Strin

本人初学,答的不好的地方请见谅,程序代码如下：importjavax.swing.JOptionPane;publicclassyuan{publicstaticvoidmain(Stringargs

1：次数最多2：在次数最多的基础上,数值最大_______________________________________________以下为程序：#include//设置最大值#defineMAX

packagea1;importjava.util.Scanner;publicclassTest1{publicstaticfloatzhouchang(floatx,floaty){return2

importjava.util.Scanner;publicclassCircle{    publicstaticvoidmain(String[]args)

Scannerscanner=newScanner（system.in)intx,y,z,temp;System.out.println("请输入x:");x=scanner.nextInt();Sy

importjava.util.Scanner;publicclassTest{publicstaticvoidmain(String[]args){System.out.print("请输入第一个整

从键盘输入一个自然数N(

importjava.util.*;publicclassCombination{publicstaticvoidmain(String[]args){VectortestData=newVector

packageABC;importjava.io.*;publicclassdistantmoon{publicstaticvoidmain(String[]s)throwsException{

BufferedReaderbuf=newBufferedReader(newInputStreamReader(System.in));System.out.print("请输入时间(注意格式必须为

publicclassJs{privatedoublea;privatedoubleb;privatedoublec;Js(doublea,doubleb,doublec){this.a=a;this

其实这种逻辑运算的,提现不错Java的面向对象的概念的,你直接写逻辑语句就好,首先判断等边,即if(a==b==c)System.out.print("该三角形是等边三角形");这样写下去就好了.希望

classOddSum//定义类{publicstaticvoidmain(Stringargs[])//main方法{intsum=0;//定义一个整形变量for(inti=1;i

用Scannerscan=newScanner(System.in);Strings=scan.next();if(s!="y"||s!="n"){System.out.println(

哥们怎么又是你来?再问：您会不会的啊再答：packagetestt;importjava.util.Scanner;publicclassTest{\x09publicstaticvoidmain(S