用c语言编写,输入任意3个整数,按照从小到大的顺序输出3个数的值
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#include<stdio.h>voidmain(){ inta,m; for(inti=0;
#include"stdio.h"intmain(){ inta,b,c,min; scanf("%d%d%d",&a,&a
/>#include <stdio.h>#include <stdlib.h>int main(){  
#includedoubletriangle(doublea,doubleb,doublec){if(a+b>c&&b+c>a&&a+c>b)return1;elsereturn0;}doublede
#include//标准输入输出函数调用需要此头文件、就是那个printf和scanf函数要用的voidmain()//主函数{inti,j,min,temp,a[10];printf("请输入:\n
#includeintmain(){inta,b,c;printf("输入三个数");scanf("d%d%d%",acb,c);intt,k;t=a>b?a:b;k=t>c?t:c;printf("
以3×4的矩阵为例:#includemain(){inta[3][4];inti,j,s;printf("Inputsomenumbers:\n");for(i=0;i
#includevoidmain(){intsum=0,i,temp;for(i=0;i
#includemain(){intn,i,s=0,sum=0;printf("请输入一个整数:");scanf("%d",&n);i=n;while(i!=0){s+=(i%10)*(i%10)*(
#includeintmain(){intn;scanf("%d",&n);if(n>0){if(n%2)printf("此数为正数且为奇数.");elseprintf("此数为正数且为偶数");}e
一:#includevoidmain(){inti,j;inta[5][3];for(i=0;i
main(){inti,n,sum=0;scanf("%d",&n);n*=2;for(i=1;i
#include#includeintmain(void){intn,sum=0,count=0,s;printf("输入一个整数:");scanf("%d",&n);while(n){s
#includeintmain(){intx,y,a;scanf("%d",&x);scanf("%d",&y);a=x*y;printf("Theaverageis%d\n",a);return0;
少了几个;赋值语句也有些问题.程序如下,编译通过.#includeintmain(){inta,b,c,t;while(scanf("%d%d%d",&a,&b,&c)!=EOF){if(a
#include“stdio.h"voidmain(){\x09inta,b,c,sum;\x09floatave;scanf("%d%d%d",&a,&b,&c);sum=a+b+c;\x09ave
intiIsRunAround(intnNum){intnCount=0;//位数intnStep=0;intnCur=nNum;intarrNumber[10];//各位数,个位到最高位intarr
#includeintmain(void){intmax,min;inta,i;printf("Input10interger:");scanf("%d",&a);max=min=a;for(i=0;
用a,b,c表示输入的3个整数;为了节约变量,把它们重新排列后,仍用a,b,c表示,并使a≥b≥c.具体操作步骤如下:第一步;输入3个整数a,b,c.第二步:将a与b比较,并把小者赋给b,大者赋给a.
程序1:#include#includeintmain(){inti;floatnum;floatsum=0;i=10;while(i--){scanf("%f",&num);sum+=num;}su