点C分线段AB为5:7,点D分线段AB为5:11
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/28 07:22:46
由题意可知:AC=(5/8)AB,AD=(3/8)ABCD=AC-AD=(1/4)ABAB=4CD=40cm
A——D—C————B∵AC:BC=5:7∴AC=AB×5/(5+7)=5/12AB∵AD:BD=5:11∴AD=AB×5/(5+11)=5/16AB∴CD=AC-AD=5/12AB-5/16AB=(
AC:CB=5:3AD:DB=3:5AC=5/8*ABDB=5/8*ABAC+DB=5/8*AB+5/8*ABAB+CD=5/4*ABCD=1/4*ABAB=4*CD=4*10=40(CM)
因为CD=AC-AD=5AB/8-3AB/8=AB/4所以AB=4CD=4*10=40cm
因为cd=ac-ad=5/12ab-5/16ab=5/48ab所以ab=48/5cd=48/5*10=96cm
10/(11/(11+5)-7/(5+7))=9610/(7/(5+7)-5/(5+11))
∵C点分线段AB为3比5D分线段AB为3比7∴AC:BC=3:5AD:BD=3:7又∵AB=40∴AC=15BD=40*7/10=28∴DC=BD+AC-AB=15+28-40=3
设AB的长为xcm,根据题意得:512x-516x=2,解得x=19.2.∴AB的长为19.2cm.
∵C点分线段AB为5:7∴AC=5/12AB∵D点分线段AB为5:1∴AD=5/6AB∴CD=AD-AC=5/12AB∵CD=5cm∴AB=12㎝
dc=ac-ad=5/8ab-3/8ab=ab/4ab=4dc=4*10=40cm
设AD=aDC=b=10CB=cAB=dd=a+10+c(a+10)/c=5/7a/(10+c)=5/11a=30b=10c=56AB=d=a+b+c=30+10+56=96
因已知线段AB,点C分线段AB为5:7,所以AC=AB*5/12因点D分线段AB为5:11,所以AD=AB*5/16若CD=5cm,即有:AC-AD=CD=5=AB*5/12-AB*5/16 得:
点C分线段AB5:7∴AC=5/12AB点D分线段AB为5:11∴AD=5/16AB∵CD=AC-AD=5㎝∴5/12AB-5/16AB=5㎝AB=48㎝
AC=5/12ABAD=5/16ABCD=AC-AD =(5/12-5/16)AB =5/48AB =5则,5/48
A——D—C——B∵AC:BC=5:7∴AC=5/(5+7)×AB=5/12AB∵AD:BD=5:11∴AD=5/(5+11)×AB=5/16AB∴CD=AC-AD=5/12AB-5/16AB=(20
因为点C分线段AB为5:7所以AC=5/12AB因为点D分线段AB为5:11所以AD=5/16AB所以CD=AC-AD=5/12AB-5/16AB=5/48AB又因为CD=5cm所以AB=5÷5/48
设线段AB长为48X则AC=5*48X/(5+7)=20XAD=5*48X/(5+11)=15XCD=AC-AD=5X=5cmx=1cmAB=48X=48cm{解释下为什么设为48x,c分ab为5:7
因为点C分线段AB为5:7所以AC=5/12AB因为点D分线段AB为5:11所以AD=5/16AB所以CD=AC-AD=5/12AB-5/16AB=5/48AB又因为CD=5cm所以AB=5÷5/48
由已知可得:ac=5/12ab,cb=7/12ab,ad=5/16ab,db=11/16ab.ac-ad=cd=10=5/12ab-5/16ab得ab=96