10x-y=69.84

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10x-y=69.84
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai

(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=4x-2y-z-5x[6y-(x+y)]+x-(3y-10z)=4x-2y-z-30xy+5x²+5xy+x-3

{ x-y/7-x+y/10=1/2 {2(x-y)+5(x+y)=3

x-y/7-x+y/10=1/2两边乘7010x-10y-7x-7y=353x-17y=35(1)2(x-y)+5(x+y)=32x-2y+5x+5y=37x+3y=3(2)(2)*3-(1)*79y

用加减法解方程组:{(x+y)/6+(x-y)/10=3 (x+y)/6+(y-x)/10=-1

(x+y)/6+(x-y)/10=3①(x+y)/6+(y-x)/10=-1②①可变为:(x+y)/6-(y-x)/10=3③②+③=(x+y)/3=2得x+y=6④②-③=(y-x)/5=-4得y-

(7x-10y)-(-10y-5x)=?

(7x-10y)-(-10y-5x)=7x-10y+10y+5x=12x再问:7x-10y+10y+5x似乎等于2x+10y再答:-10y+10y=0

已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y

先化简[(x²+y²)-(x-y)²+2y(x-y)]/4y[(x²+y²)-(x-y)²+2y(x-y)]/4y=[x²+y&s

已知x-y-3绝对值+(2x+2y+10)的平方=0,则(x+y)(x-Y)=

x-y-3绝对值+(2x+2y+10)的平方=0X-Y-3=0X-Y=32X+2Y+10=0X+Y=-5(x+y)(x-Y)=3X(-5)=-15

已知/x/+x+y=10,/y/+x-y=12.求x+y的值

|x|+x+y=10|y|+x-y=12两式相加得|x|+|y|+2x=22.(1)两式相减得|x|-|y|+2y=-2.(2)所以-|y|+2y<0若y>0,则显然-y+2y<0,即y<0,矛盾若y

y=ln(1+x),求y^10(x)?

若是y的10次,我也不必说了若是y的10阶导数1:1/(1+x)2:-(1+x)^(-2)3:2(1+x)^(-3)……10:9!(1+x)^(-9)

已知x,y满足约束条件{2x+5y>=10,2x-3y>=-6,2x+y

在坐标系中先作2x+5y≥10对应的直线2x+5y=10,取直线上方区域;然后作2x-3y≥-6对应的直线2x-3y=-6,把y的系数变为正,可知取直线下方区域;最后作2x+y≤10对应的直线2x+y

解方程组:(x+3)(y-2)=(x-3)(y+10),(x+1)(y+3)=(x-2)(y+12)

.死算呗xy-2x+3y-6=xy+10x-3y-30,2x-y=4xy+3x+y+3=xy+12x-2y-24,3x-y=92式减1式,x=5,y=6

X+Y=7(100X+Y)-(10Y+X)=(10Y+X)-(10X+Y)

(100X+Y)-(10Y+X)=(10Y+X)-(10X+Y)100X+Y-10Y-X=10Y+X-10X-Y99X-9Y=9Y-9X-18Y=-108XY=6X把Y=6X代入X+Y=7得X+6X=

解方程组:2/(x+y)+5/(x-y)=18 9/(x+y)-10/(y-x)=66

2/(x+y)+5/(x-y)=189/(x+y)-10/(y-x)=66设x+y=a,x-y=b,原方程化为2/a+5/b=18-----1(1)9/a+10/b=66-------(2)(2)-(

已知2x-y=10,求式子[(x^2+y^2)-(x-y)^2+2y(x-y)]/4y (4xy-2y²)/4

已知2x-y=10,式子[(x^2+y^2)-(x-y)^2+2y(x-y)]/4y=[x^2+y^2-x^2+2xy-y^2+2xy-2y^2]/4y=[4xy-2y^2]/4y=2y(2x-y)/

解方程组:2/(x+y)+5/(x-y)=18 9/(x+y)-10/(y-x)=66

另a=1/(x+y),b=1/(x-y);则2a+5b=18;9a+10b=66;解得a=6,b=6/5;即       &nbs

解方程组x+y/6+x-y/10=3,x+y/6+y-x/10=-1

①-②可得:x-y/10-y-x/10=4x-y/5=4x-y=20——③①+②可得:x+y/3=2x+y=6——④由③④可得:x=13,y=-7

(x+y)(x+y+10)+25=0 x-y=3.求x,y的值

(x+y)(x+y-10)+25=0设x+y=aa(a-10)+25=0a²-10a+25=0(a-5)²=0a=5∴x+y=5x-y=3x=4y=1

第一道:已知X的平方+Y的平方-4X+10Y+29=0.求分式X+Y/X-Y+X-Y/X+Y的值.

(1)x^2+y^2-4x+10y+29=0x^2-4x+4+y^2+10y+25=0(x-2)^2+(y+5)^2=0x=2y=-5剩下的自己解下面两个题目是不是写错了,没看懂

已知实数x,y满足|x|+x+y=10、x+|y|-y=12,则x+y的值?

若x≤0,|x|=-x|x|+x+y=10y=10代入x+|y|-y=12得x=12>0矛盾,∴x>02x+y=10①若y≥0,x+|y|-y=x=12y=10-2x∴yx-2y=12②联立①②解得x