汇编语言编写出一个解Y＝F(X)的查表程序

这样：movds:[0],0movax,0ff37h;假设用这个数字movdx,0001hmovcx,0FHs:movbx,dx；bx从01h开始addbx,ax；与运算,cmpbx,dx；如果相等位

assumecs:code,ds:datadatasegmentxdwydwzdwresultdwdataendscodesegmentstart:movax,datamovds,axmovax,xi

M文件中输入如下代码：functionf1=aa();disp('请输入三个数a,b,c:');a=input('a=');b=input('b=');c=input('c=');f1=min(min

（1）由于:f(x)+f(y)=f(x+y)则:令x=y=0,有f(0)+f(0)=f(0),所以f(0)=0再令y=-x有f(x)+f(-x)=f(0)=0,所以f(-x)=-f(x)设x1>x2,

用系统内置的函数#include#includevoidmian(){doublepower,f;power=pow(x,y);f=power;printf("f(x,y)=%f",pow(x,y))

CodeSegmentAssumeCS:Code,DS:CodeEnterCRLFProcNearmovdl,0dhmovah,2int21hmovdl,0ahint21hretEnterCRLFEn

(x,y)=x+y(x>=0&y>=0)f(x,y)=x+y*y(x>=0&y

MOVEAX,AMOVEBX,BMOVECX,CADDEAX,EBXSUBEAX,ECXMOVY,EAX再问：运行不了，好多错误啊再答：我假设你声明了A,B,C,Y这几个变量。。具体问题有疑问可以私密

计算表达式：f=a*(b+c)/（d-e）假设a,b,c,d,e,f都是定义好的标号,并且大小都是word,那么实现指令如下movax,c;计算(b+c)addax,bmovcx,d;计算(d-e)s

DATASEGMENTy1DB1y2DB0y3DB-1yDB;(此处存放判定结果)xdb;(此处设定要用的x,代换调“?”即可)DATAENDSCODESEGMENTASSUMECS:CODE,DS:

很简单的#includeusingnamespacestd;voidmain(){doublex,y;cin>>x;if(x

等会帮你编一个.编好了：datasegmentxdw?ydw?zdw?wdw?dataendsstacksegmentstack\x09db32dup(?)stackendscodesegmentas

DATASEGMENTXDW3YDW-5ZDW1MAXDWDATAENDSCODESEGMENTASSUMECS:CODE,DS:DATASTART:MOVAX,DATAmovds,axMOVAX,X

clearclcx=[50100150200250300350400450 500];y=[4080120160200];z=[0.050.050.050.050.050.250.150.1

datasegmentvaldb100dup(0)codesegmentassumecs:codeds:datastart:movax,datamovds,axleasi,valmovbx,1movc

ab都是多少并且打算采用什么算法再问：a,b可以随便赋值直接计算求值就可以了

assumecs:code,ds:datadatasegmentresultdb0,1,4,9,16,25,36,49,64,81xdb4dataendscodesegmentstart:movax,

forx=0:0.1:100if(x

symstb=1.09;g=9.79;h=7.86;y=h+(g-0.2233)*(1-exp(-b*t))/b^2-(g-0.2233)*t/b;dy1=diff(y);fori=1:8dy(i)=

1.DATASEGMENT；定义数据段XDB32,-43,76,95,-1YDB-78,127,-128,-125,88SDB5DUP(?)DATAENDSCODESEGMENT；定义代码段ASSUM