求下列函数的导数y=ln(x a2 x2)
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/30 09:26:32
y'=1/sinx*(sinx)'=cosx/sinx
/>y=ln(1+x^2)y'=2x/(1+x^2)y''=[2(1+x^2)-2x(2x)]/[(1+x^2)^2]=(2+2x^2-4x^2)/[(1+x^2)^2]=2(1-2x^2)/[(1+
等于(-1)的n-1次方*(n-1)!*(1+x)的-n次方.*代表乘号再有不懂的可以继续问我
y=ln(x+1)的导数为y!=1/(x+1)y!的导数y!=-1/(x+1)^2即为y的二阶导数
直接两边对x求导,得1/y*(-1/y2)*dy/dx=1/xy*(y+xdy/dx)下面会了吧
y=(ln(ln(x))'/ln(ln(x))=(ln(x))'/(ln(x)(ln(ln(x)))=1/(xln(x)ln(ln(x)))
y'=1/xx>0x
y'=arctanx加x/(1加x^2)-x/(1加x^2)=arctanx再问:有详细步骤吗?
两边求导(y'x-y/x^2)/[1+(y/x)^2]=x+yy'/(x^2+y^2)^1/2整理y'x-y=(x+yy')(x^2+y^2)^1/2
应该是1/cosxsinx
复合函数求导:y'=1/tanx*(tanx)'=1/tanx*(secx)^2=1/(sinxcosx)=2/sin2x再问:1/(sinxcosx)=2/sin2x,这个怎么来的呀?
y'=[cos(10-3x^2)]'/cos(10-3x^2)=-sin(10-3x^2)*(10-3x^2)'/cos(10-3x^2)=-sin(10-3x^2)*(-6x)/cos(10-3x^
(1)y′=(x2)′sinx+x2(sinx)′=2xsinx+x2cosx.(2)y′=1x+1+x2•(x+1+x2)′=1x+1+x2(1+x1+x2)=11+x2.(3)y′=(ex+1)′
(1)这是复合函数的求导=(2-3x)的导数乘以ln根号下(2-3x)的导数,即为-3[1/(2-3x)](2)同样复合函数=x的导数乘以e^(2x+1)+x乘以e^(2x+1)的导数,即为e^(2x
x=yln(xy),等式两端对x求导,1=dy/dx+y[1/ln(xy)][y+x(dy/dx)]=dy/dx+y/ln(xy)+xdy/dx,整理得(dy/dx)(1+x)=1-y/ln(xy),
y=0.5*[ln(1-x)-ln(1+x^2)]y'=0.5*[1/(x-1)-2x/(x^2+1)]哦,不好意思y''=(x^2-1)/[(x^2+1)^2]-1/[2*(x-1)^2]还用再进一
y=x+lny两边求导:y'=1+y'/yy'(1-1/y)=1y'=y/(y-1)y‘’=[y'(y-1)-y*y']/(y-1)²=[y-y²/(y-1)](y-1)²
IN(1+X)的导数是1/(1+x)sin2x的导数先对sin2x求导得到cos2x再对2x求导是2所以最后结果1/(1+x)+2cos2x这个求导很简单楼主要加强学习啊再问:报的自考,前两天刚给的书