检验2x-2 1=-2 1x 2
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/29 03:26:28
examinationofthepairingx2
设(x²-1)/(x²+2x)=t则8t+3/t=118t²-11t+3=0(8t-3)(t-1)=0解得t=3/8或t=11.t=3/8(x²-1)/(x
后面的x²+11x-708有误吧!再问:没有题目就这样能不能帮我再答:那我就试试:原式为:1/x2+x+1/x2+3x+2+1/x2+5x+6+1/x2+7x+12+1/x2+9x+20=5
1.5+2X=5X5x-2x=1.53x=1.5x=0.51.5+2*0.5=2.5=5*0.5
x/(2x^2-11x-21)=(x+7)/(x^2-12x+35)x/(2x+3)(x-7)=(x+7)/(x-5)(x-7)x/(2x+3)=(x+7)/(x-5)x(x-5)=(x+7)(2x+
2(x²-7x)²-21(x²-7x)+10=0[(x²-7x)-10][2(x²-7x)-1]=0所以x²-7x-10=0或者2x
x2+2x+2=(x+1)^2+1=(√21)^2+1=22
1.5(4x-2x)=4.81.5*2x=4.83x=4.8x=1.6检验:左边=1.5×(4×1.6-2×1.6)=1.5×(6.4-3.2)=4.8=右边所以x=1.6是方程的解
2x+5x+3+4-x/2+2x+x-2=019x/2=-5x=-19/10检验:带入x是、原式=0
x2+x+1=2/(x2+x)(X²+x)²+(x²+x)-2=0(x²+x+2)(x²+x-1)=0∴x²+x-1=0x=(-1±√5)/
1/(x2+x)+1/(x2+3x+2)+1/(x2+5x+6)+1/(x2+7x+12)=1/x(x+1)+1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)=1/x-1/
2x+0.4x=482.4x=48x=48/2.4x=208x-x=14.77x=14.7x=14.7/7x=2.135x+13x=9.648x=9.6x=0.55(x+3)=355x+15=355x
(x²+x)(x²+x-2)=-1把(x²+x)看成整体(x²+x)[(x²+x)-2]=-1运用乘法分配率(x²+x)²-2(x
x²+x-1/(x²+x)=3/2两边同时乘以(x²+x)得:(x²+x)²-1=3(x²+x)/22(x²+x)²-3
21x*x-14x=73x*x-2x=16x*x-4x=26x*x-4x+5=7这样说你能明白吧.
3x-x=-3-22x=-5X=-5÷2x=-2.53×-2.5+2=-3-2.5-7.5+2=-5.55.5=5.5
2(X-5)=0.182x-10=0.182x=10.18x=5.09检验;把x=5.09代替到2(X-5)=0.18得0.18=0.18所以x=5.09是2(X-5)=0.18的解
令a=x+1/xa²=x²+2+1/x²2(a²-2)-9a+14=0(2a-5)(a-2)=0x+1/x=5/22x²-5x+2=0(2x-1)(x
解题思路:利用一元二次方程计算解题过程:最终答案:略