c语言输入圆的半径,求圆的面积显现出来

#includemain(){\x09floatS(floatr);\x09floatr;\x09printf("inputr:");\x09scanf("%f",&r);\x09printf("圆面

#includeintmain(){floatr,s,l;scanf("%f",&r);s=3.14*r*r;l=2*3.14*r;printf("s=%f,l=%f\n",s,l);return0;

#include#definepi3.141592653intmain(){doubler;printf("输入半径：\n");scanf("%lf",&r);printf("周长为：\n");pri

#definePI3.1416//后面不需要;#include"stdio.h"//注意关键字之间要有空格intmain(){floatr,s,c;scanf("%f",&r);c=2*PI*

在输入半径的时候,语句改成scanf("%d",&r);不过你最好将半径定义成float型变量,格式的问题

scanf("%d",&r);

voidmain(){floatr,s,l;floatpi=3.1415;printf("输入一个圆的半径:\n");scanf("%f",&r);if(

#include#definePI3.1415926\x05\x05voidmain()\x05{\x05doubler,s;scanf("%f",&r);s=PI*r*r;\x05printf("A

楼上的方法应该没错,可感觉对于表现java面向对象的特性没有表现出来,下面是我写的,应该非常清楚明了了importjava.io.BufferedReader;importjava.io.InputS

#includeintmain(){intr;printf("请输入r：");scanf("%d",&r);printf("面积是：%f\n",2*3.1415*r*r);return0;}再问：没有

1.#includeintmain(){floatr,s,l,v;printf("请输入半径\n");scanf("%f",&r);s=3.14*r*r;l=2*3.14*r;v=4.0/3.0*3.

#includevoidmain(){floatr,d,Cs;cout

#includeintmain(){doubleR;while(scanf("%lf",&R)!=EOF){printf("%lf\n",R*R*3.14);}return0;}

#include#includepublicvoidmain(){doublea,b,c;scanf("%lf%lf%lf",&a,&b,&c);doublearea,preimeter;preime

#includeintmain(){intr=0;floata=0,l=0;scanf("%d",&r);a=r*r*3.14;l=r*2*3.14;printf("面积:%f,周长:%f",a,l)

#include<stdio.h>#include<math.h>double CalcArea(double a,double b,double

#include#includemain(){doublearea,length;doubler=pi=3.1215926area=pi*r*r；length=2*pi*r；}

#include"stdio.h"#definePI3.141592653//定义πintmain(void){floatC,A,V,r;printf("请输入半径：");//提示输入scanf("%

#include#include#defindPI3.141592654main(){doublevolume;floatradius;printf("Inputradius:");scanf("%f

#...intr,b,dsin