c语言输入一个正整数n,输出0-n之内的所有奇数.
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#include"stdio.h"intmain(){\x09inti,j,n;\x09inta[12];\x09intmin,mx;\x09scanf("%d",&n);\x09for(i=0;i
intmain(intargc,char*argv[]){intinput;intret,num;printf("Inputaint:");scanf("%d",&input);for(;;){num
#includevoidmain(){\x09intn,i,j,t,a[10000];\x09printf("请输入正整数N:");\x09scanf("%d",&n);\x09printf("请依次
#includevoidmain(){inti,N,sum;while(scanf("%d",&N)){sum=0;for(i=1;i
#includeintmain(){intn;scanf("%d",&n);do{printf("%d",n%10);}while(n/=10);printf("\n");return0;}
#includemain(){intn,c=0;printf("输入一个小于等于一万的整数:");scanf("%d",&n);if(n>10000&&n
#include<stdio.h>int main(){ int n; do
只学循环完全可以办到,关键是要动脑啊#includevoidmain(){\x09intn,m,max,i;\x09max=0;\x09printf("PleaseInputANumber:\n");
#include <stdio.h>void main (){ int a[10]; int i,k=0,n,min,
#includeintmat[10][10];voidmain(){intn,i,j;intok=1;scanf("%d",&n);for(i=0;i
#include#includevoidmain(){intn;printf("pleaseinputn:");scanf("%d",&n);inti,j,sum;for(i=1;i
#includevoidmain(){\x09inti,n;\x09inta[10];\x09ints,p;\x09printf("n:");\x09scanf("%d",&n);\x09for(i=
使用了数组的动态分配,看不懂的话我还有其他方案#include#includeboolprime(intnum){boolflag=true;if(num
vari,j,n:longint;z:boolean;beginreadln(n);writeln(2);fori:=3tondobeginz:=true;forj:=2toi-1doifimodj=
#includemain(){inti,j,N,t,k=0;intscore[100];printf("请输入整数的个数N:\n");scanf("%d",&N);printf("请输入N个整数:\n
#includemain(){intn,sum=0;scanf("%d",&n);for(inti=0;i
#includeintmain(void){intn=0,m=0,i=0,j=0,k=0;scanf("%d",&n);while(n--){\x09scanf("%d",&m);\x09for(j=
第一个for(i=0;i
#includemain(){intn,i,j;printf("inputainteger:");scanf("%d",&n);printf("\n");for(i=1;i
#include#defineNUM20voidmain(){longn;intdata[NUM]={0},len=0;scanf("%d",&n);do{data[len++]=n%10;n/=10