c语言编程题 输入一个数,求其位数
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输入两个正整数m和n,求其最大公约数和最小公倍数.用辗转相除法求最大公约数算法描述:m对n求余为a,若a不等于0则m0){m_cup=m;n_cup=n;res=m_cup%n_cup;while(r
main(){inta,b,c;scanf("%d%d%d",&a,&b,&c);if(a
#include<stdio.h>#include<math.h>int min(int x,int y)\x09\x09//求m和n的最小值{\
#includeintmain(){intm,n;intm_cup,n_cup,res;/*被除数,除数,余数*/printf("Entertwointeger:\n");scanf("%d%d",&
#include int main() { int m, n; int m_cup, n_cup,
例如:2的3次方#include#includeintmain(intargc,char*argv[]){printf("%f\n",pow(2,3));//第一个参数是底数(double),//第二
intmain(){floatc,f;printf("pleaseinputthef=");scanf("%f",&f);c=5/9*(f-32);printf("thec=%f",c);}再问:你运
#includevoidmain(){intx,a,b,c;scanf("%d",&x);a=x/100;b=x/10%10;c=x%10;x=c*100+b*10+a;printf("%d",x);
#includeintmain(){inta,sum=0;scanf("%d",&a);while(a){sum+=a%10;a/=10;}printf("sum=%d\n",sum);return0
inti=2123;intone,two,three,four;one=i%10;//各位two=(i/10)%10;//十位three=(i/100)%10;//百位four=(i/1000)%10
利用辗除法公约数,再算公倍数.#include <stdio.h>void main(){ int a,&nbs
#includeintmain(){inti;voidfun(inta);printf("输入数字:");scanf("%d",&i);fun(i);return0;}voidfun(inta){if
程序你看看吧,有问题再问,/>#include<stdio.h>int main(){ int i,t,t1; int a[10];&nb
#includevoidmain(){inti,j,k,m;printf("inputdata:");scanf("%d",&m);/*输入一个3位数*/i=m/100;j=(m-100*i)/10;
给你一个输出来是正的正三角行图案:/*输出一个正的正三角行图形*/#includevoidmain(){inti,j,x,n,count,k,m,q,p,v;scanf(“%d%d”,&n,&x);c
最大公约数:intGcd(inta,intb){if(a%b==0)returna;return(b,a%b);}最小公倍数:intGbs(inta,intb){returna*b/Gcd(a,b);
#includeintmain(){intn,i,j;doublesum=0.0;printf("请输入项数n:\n");scanf("%d",&n);if(n1000)printf("输入数字超出范
#include"stdio.h"main(){intx;printf("请输入一个整数");scanf("%d",&x);if(x%2==0)printf("%d是偶数\n",x);elseprin
intn,i=0;scanf("%d",&n);while(i
#includeintmain(){inta,b;scanf("%d%d",&a,&b);/*输入两个整数a和b*/printf("%d\n",a+b);/*输出a和b之和~*/return0;}