C语言编写整形数个位数字之和-搜答案-神马作文网

#includeintmain(){\x05inta[10]={1001,1234,2234,2534,4444,6767,7896,6435,1098,8796};\x05inti;\x05intj

main(){inti;for(i=100;i

#includeintfun(intn){ints=0;while(n){s+=n%10;n=n/10;}returns;}main(){intn;scanf("%d",&n);printf("%d\

1#include"stdio.h"main(){intn,i;scanf("%d",&n);printf("%d",n/100+n%100/10+n%10);system("PAUSE");}2#i

#include "stdio.h"void main(){ int n,sum=0; printf(&q

#includeintmain(){intx;inta[20];scanf("%d",&x);inti;for(i=0;x>=10;i++){a[i]=x%10;x=x/10;}

你写的scanf就提出了要求的输入是“数a”“逗号”“数b”,你既然没有给出逗号,那就一直没有给b赋值,你也没有给b一个初始化的值,那么得出的结果就是一个随机数.可以把逗号去掉,这样两个数字之间用个空

#include"stdio.h"main(){inti,sum=0;for(i=126;i再问：能不能根据这个改下？？？？谢谢啦！！！#includeintmain(){inta;for(a=1

#include"stdio.h"main(){intdigit,k,m,s;for(k=1;k

#includevoidmain(){inti=0,j=0,k=0;for(i=1;i

#include<stdio.h>int main(void){ int n,count = 0;&n

for(inti=0;i

#includeintmain(){inta,b,c,min,max;printf("请输入三个数,用空格键隔开");scanf("%d%d%d",&a,&b,&c);min=ac?b:c);prin

仅需要一个循环而已#includevoidmain(){inti=0;intj,k;for(j=100;j

#includeintmain(){intnum;inta,b,c;scanf("%d",&num);a=num/100;b=(num%100)/10;c=num%10;printf("a=%d,b=

#includeusingnamespacestd;voidmain(){inta,b,c;coutb;c=a+b;cout

太简单了吧#includevoidmain(){intA,bai,shi,ge;printf("请输入一个三位整数A：");scanf("%d",&A);bai=A/100;shi=A%100/10;

#includeintmain(intargc,char*argv[]){intn,s;for(inti=100;i

#includeintn,m=0;intmain(){scanf("%d",&n);while(n){m+=n%10;n/=10;}printf("%d\n",m);return0;}再问：看不懂。能

简单再问：。。。。这好像不是我要的答案再答：#include"stdio.h"intgcd(intx,inty)//欧几里得辗转相除法求两数的最大的公约数{intm;if(x