C语言求1! 2! 3! ... n!的和.
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您好!很高兴为您解答.解释如下:#includevoidmain(){inti,j,n;longintt=1,sum=0;//必要的初始化,保证后面for循环的语句“sum=sum+t;”能正常执行.
#includevoidmain(){inti,n;intm=1;intsum=0;printf("请输入n的值:");scanf("%d",&n);for(i=1;i
#includevoidmain(){inti,a=0,sum=0;for(i=1;;i++){a+=1;sum+=a;if(sum>1000){printf("n:%d\nsum:%d\n",i,s
#include <stdio.h>int sumn(int n,int *flag){ (*flag)++; if(n==1)
你自己写点,有问题我帮你调试.这个不难再问:不会写啊再答:编程就是个熟练活儿,多练习就会了# include <stdio.h>int main(void){
#include#includeintsum(intn,intk){inti;ints=0;for(i=1;i
#include <stdio.h>int main(){\x09int n,i,sum=1;\x09scanf("%d",&n)
intsum=0,i=0,n=?;//n的值你可以从外面输入for(i=1;i
#include"不同软件头文件不一样"main(){inti,n,s=0;scanf("%d",&n);for(i=1;i
#includeintmain(){\x09inti,n;\x09floatsum=0;\x09printf("请输入n:\n");\x09scanf("%d",&n);\x09for(i=1;i
#includeintmain(){\x09intn;\x09unsignedinttmp=0;\x09printf("pleaseinputadata:");\x09scanf("%d",&n);\
//#include"stdafx.h"//vc++6.0加上这一行.#include"stdio.h"voidmain(void){intn,i,sum,x;printf("Enteraninteg
#include<stdio.h>void main(){ int i,k,sum=0;  
给你个小例子参考一下:#includeintmain(){inti,n=10;doublenSum=0.0;for(i=1;i
#include <stdio.h>#include <string.h>main(){\x05int n=0;\x05int s=0;
intfactorial(intn){if(n
输入的a不能太大,否则整型会溢出的!#includemain(){inta,b,c,s,t;s=1;t=0;//1----->0scanf("%d",&a);for(c=1;c
#includeintmain(){intn,i;longa,sum=1;printf("请输入一个奇数:\n");scanf("%ld",&n);for(i=3,a=1;i
intN(intx){if(x==0){return1;}else{returnx*N(x-1)}}intiRet=0;for(inti=1;i
#includevoidmain(){doubles=1.0;inti,N;scanf("%d",&N);for(i=0;i