c语言 随机产生一个5*5的矩阵

#include#includevoidRAND_RECTANGE(intx);intmain(void){intx;srand(time(0));x=rand()%10;RAND_RECTANGE(

and(m,n)产生mxn,0~1均匀分布的随机矩阵

#include<stdio.h>#include<stdlib.h>#defineM10#defineN10intmain(void){inti=0,j=0;intArr[M

刚答过一个#include#include#include#includeintmain(){charr[7];inti,j,k,t,f;FILE*fp;fp=fopen("d:\\file

"求两矩阵的乘积“是什么意思?再问：就是求生成的那两个矩阵啊再答：PrivateSubCommand1_Click()Dimb(1To3,1To4)AsIntegerDimc(1To4,1To3)As

错了,没写路线,重改了一下：#include#include#include#include#definerandomize()srand((unsigned)time(NULL))intM[10][

#include#include#include#includeintmain(){\x05\x05charr[7];\x05inti,j,k,t,f;\x05srand(time(0));\x05f

思路：分别产生个、十、百位上的随机数,依次组合在一起#include#include#includeintmain(){inti,tmp;num=0;srand((unsigned)time(NULL

if(j==4)\x09\x09\x09\x09printf("%d\n",max);去掉if(j==4)加大括号.改成这样:#defineM3#defineN5#includevoidmain(){

#include <stdio.h>#include <stdlib.h>#include <time.h>int mks(

#include#include#include#defineN1000intfun(inta[],intnum);voidmain(){inti,a[N],b,num,n;printf("\n请输入

'定义事件由单击按钮触发providesubcommand1_click()'定义数组dima(1to5,1to5)asinteger'生成矩阵数组元素fori=1to5forj=1to5a(i,j)

Dima%(1To6,1To6),b%(1To6,1To6)PrivateSubCommand1_Click()Fori=1To5Forj=1To5a(i,j)=Int(Rnd*90+10)Pictu

ound(rand([1020])*7)+3%不需要整数的话,把round去掉就行了

每一行中的A（i）必须排在对应的B（i）之前这一句是什么意思?

若要放进5*6的矩阵中A,T=rand(5,6);A=T;

m=5;n=5;%矩阵大小m×nA=round(9.*rand(m,n));%5阶矩阵,9的随机整数形成sh=0;xa=0;dia=0;ci=0;kao=0;fori=1:mforj=1:nifj>i

//---------------------------------------------------------------------------#include<stdio.h>

#include#include#includeintmain(){inti,j;inta[10]={2,5,9,35,44,37,63,6,17,28};srand((unsigned)time(N

输出结果哪里不对可以说下不?再问：有发代码的图片，有看见么？如果看不见的话，请看私信……拜托了~再答：#include"stdio.h"#include"time.h"#include"stdlib.