cosx 根号3sinx 表示成

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cosx 根号3sinx 表示成
3/2cosx-根号3/2sinx

(3/2)cosx-(√3/2)sinx=√3[(√3/2)cosx-(1/2)sinx]=√3[sin(π/3)cosx-cos(π/3)sinx]=√3sin(π/3-x)=-√3sin(x-π/

已知tanx=根号3,求sinx cosx sinx+cosx/sinx-cosx

/>tanx=√3则x=kπ+π/3,k∈Z(1)k是偶数,则sinx=√3/2,cosx=1/2(2)k是奇数则sinx=√3/2,cosx=1/2(sinx+cosx)/(sinx-cosx)的值

已知sinx=根号3cosx,求sinx,cosx,tanx

用sinx2+cosx2=1再问:可以帮我把顺序写出吗。再问:谢谢。再答:就是3cos2x+cos2x=1再答:然后cosx=正负0.5就行了再问:就只有后面这两个步骤吧再问:还是前面那个也要再问:s

已知向量m=(2sinx,cosx-sinx),n=(根号3cosx,cosx+sinx),F(x)=m.n

F(x)=m.n=2根号3sinxcosx+cos^2x-sin^2x=根号3sin2x+cos2x=2sin(2x+π/6)

方程sinx+根号3cosx=2

sinx+根号3cosx=22(sinx/2+根号3cosx/2)=2sinx/2+根号3cosx/2=1sinxcosπ/3+cosxsinπ/3=1sin(x+π/3)=1所以x+π/3=2kπ+

化简 (1)3根号15sinx+3根号5cosx (2)根号3sinx/2+cosx/2

(1)3根号15sinx+3根号5cosx=6根号5((根号3)/2sinx+1/2cosx)=6根号5(cos10°sinx+sin30°cosx)=(6根号5)sin(x+30°)(2)根号3si

求定积分∫(sinx-cosx)/3次根号下(sinx+cosx) [0,π/2]

[0,π/2]∫(sinx-cosx)/(sinx+cosx)^(1/3)dx=[0,π/2]∫-d(sinx+cosx)/(sinx+cosx)^(1/3)=[0,π/2]∫-d(sinx+cosx

根号下[(sinx)三次方-(cosx)三次方}怎么等于|cosx|(sinx)^3/2

不等于.如果等于,则两边平方,有sinx3-cosx3=cosx2sinx3移项有cosx3=sinx3(1-cosx2)=sinx5这个肯定不一定满足.

几道辅助角公式题~sinx+cosx=?sinx-cosx=?sinx+根号3*cosx=?sinx-根号3*cosx=

sinx+cosx=√2(sinxcosπ/4+cosxsinπ/4)=√2sin(x+π/4)sinx-cosx=√2(sinxcosπ/4-cosxsinπ/4)=√2sin(x-π/4)sinx

根号3sinx+cosx化简

=2*(根号3sinx/2+cosx/2)=2(sinx*cos30°+cosxsin30°)=2sin(x+30°)

根号3sinx-cosx咋化简?

√3sinx-cosx=2(sinxcosπ/6-cosxsinπ/6)=2sin(x-π/6)

化简sinx(sinx+根号3·cosx)

=(sinx)^2+√3sinxcosx=(1-cos2x)/2+√3/2(2sinxcosx)=1/2-1/2cosx+√3/2sin2x=1/2+sin(-π/6)cos2x+cos(-π/6)s

cosx+根号3sinx=根号3求x

π/6+2kπ(k属于Z)

y=根号3cosx+sinx

y=√3cosx+sinx=2[(√3/2)cosx+(1/2)sinx]=2(sinπ/3cosx+cosπ/3sinx)=2sin(x+π/3)所以它的最小正周期=2π;图像的对称轴为:x=kπ+

y=根号3cosx+sinx值域

不用画图值域就是[-2,2]因为y=cosx的值域是[-1,1]

y=cosx(根号3sinx+cosx)化简

Y=sinx*cosx*√3+cos^2x=√3/2*sin2x+1/2*cos2x+1/2=sin(2x+∏/6)+1/2.

y=sinx+根号3cosx 2*(sinx/2+根号3cosx/2)吗?

不管怎么写,都是有意义的.它只是函数,不存在成立不成立的问题.

已知向量m=(cosx+sinx,根号3 cosx) 向量n=(cosx-sinx,2sinx)

没错,f(x)=2sin(2x+π/6)周期T=2π/2=π因为-1≤sin(2x+π/6)≤1f(x)max=2f(x)min=-2

根号2(sinx-cosx)

原式=2(sinx*√2/2-cosx*√2/2)=2(sinxcosπ/4-cosxsinπ/4)=2sin(x-π/4)