1.4x 2.4X=36解方程
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设(x²-1)/(x²+2x)=t则8t+3/t=118t²-11t+3=0(8t-3)(t-1)=0解得t=3/8或t=11.t=3/8(x²-1)/(x
等式两边同时乘以(x+3)(x-2)(x+2)就可以去分母了
4x+24-2x=382x=14x=7再问:亲,请问24怎么来的再答:12*2再答:(12-x)*2=24-2x再问:哦,谢谢
(2x^2-4x-3)/(x^2-2x-1)-3=0{(2x^2-4x-3)-3(x^2-2x-1)}/(x^2-2x-1)-=0{-x^2+2x}/(x^2-2x-1)=0-x(x-2)/(x^2-
令a=x2+x(a+1)(a+12)=42a2+13a+12=42a2+13a-30=0(a+15)(a-2)=0a=-15,a=2x2+x=-15x2+x+15=0无解x2+x=2x2+x-2=(x
(x^2+x)^2-4(x^2+x)-12=0设x^2+x=m那么有m^2-4m-12=0(m+2)(m-6)=0解得m1=-2,m2=6,即x^2+x=-2,x^2+x=6当x^2+x=-2时,x^
(x2-x)=3(x2+x)x2-x=3x2+3xx2-3x2-x-3x=0-2x2-4x=0-2x(x+2)=0x1=0x2=-2
4x²=11x4x²-11x=0x(4x-11)=0x=0或4x-11=0∴x1=0,x2=11/4.
令x²+x=t原方程变为t+1=6/tt²+t-6=0(t+3)(t-2)=0则t=2或-31)x²+x=2x²+x-2=0(x+2)(x-1)=0x=-2或x
x2+x+1=2/(x2+x)(X²+x)²+(x²+x)-2=0(x²+x+2)(x²+x-1)=0∴x²+x-1=0x=(-1±√5)/
设t=x²-x则原式可化为t²-4(2t-3)=0即t²-8t+12=0(t-2)(t-6)=0所以t1=2,t2=6即x²-x=2或者x²-x=6解
两边乘x(x+1)(x-1)2(x-1)+3(x+1)=4x2x-2+3x+3=4x5x+1=4xx=-1经检验,x=-1时分母x+1=0增根,舍去方程无解
(x^2+2x)^2-4(x^+2x)+3=0[(x^2+2x)-3][(x^2+2x)-1]=0[x^2+2x-3][x^2+2x-1]=0(x-1)(x+3)(x^2+2x-1)=0剩下的你解没问
(x²+x)(x²+x-2)=-1把(x²+x)看成整体(x²+x)[(x²+x)-2]=-1运用乘法分配率(x²+x)²-2(x
x²+x-1/(x²+x)=3/2两边同时乘以(x²+x)得:(x²+x)²-1=3(x²+x)/22(x²+x)²-3
X2+2X+2=8X+4x²-6x=2x²-6x+9=11(x-3)²=11x-3=±√11x=3±√11
(x-4)/(x²+x-2)=1/(x-1)+(x-6)/(x²-4)(x-4)/(x-1)(x+2)=1/(x-1)+(x-6)/(x-2)(x+2)(x-4)(x-2)=(x-
5x-x+4=104x=6x=1.5
-x^2+4x=0-x(x-4)=0-x=0x-4=0x=0或者x=4
方程变形得:(x2-x-6)(x2-x+2)=0,可得x2-x-6=0或x2-x+2=0(此方程无解),解得:x1=3,x2=-2.