当a=()时2a=a
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原式=(a+1)/(a-1)-[a/(1/a)]/(a-2a+1)=(a+1)/(a-1)-a/(a-1)=[(a+1)(a-1)-a]/(a-1)=(a-1-a)/(a-1)=-1/(a-1)a=-
a=1/(√3+2)=(2-√3)/(√3+2)(2-√3)=(2-√3)/(4-3)=2-√3a-1=1-√3
a=1/(√5+2)=(√5-2)/(√5+2)(√5-2)=(√5-2)/(5-4)=√5-22
等差1+15=4+12a1+a15=a4+a12所以a1-a4-a8-a12+a15=2则-a8=2a8=-21+15=8+8所以a1+a15=a8+a8=-4S15=(a1+a15)*15/2=-3
原式=(a+1)(a-1)/(a-1)-√(a-1)²/a(a-1)=a+1-(1-a)/a(a-1)=a+1+1/a=2-√3+1+1/(2-√3)=3-√3+(2+√3)/(2-1)=3
a=√3>1a-1>0|a-1|=a-1原式=[(a-1)²/(a-1)]-√(a-1)²/a(a-1)=(a-1)-|a-1|/a(a-1)=a-1-(a-1)/a(a-1)=a
15a^2-{-4a^2+[5a-8a^2-(2a^2-a)+9a^2]-3a}=15a^2-{-4a^2+[5a-8a^2-2a^2+a+9a^2]-3a}=15a^2-{-4a^2+[6a-a^2
当A大于0时,a分之|a|=1.当a小于0时,|a|分之a=-1
原式=a-a-b+a+2b-a-3b+a+4b+…+a+100b-a-101b=-51b,当a=12,b=13时,原式=-17.
原式=(a-1)²/(a+1)(a-1)+2a(a-2)/(a+1)(a-2)=(a-1)/(a+1)+2a/(a+1)=(3a-1)/(a+1)=(√3-1)/(√3/3+1)=3(√3-
2a^2-3a-4a^2+5a-1=-2a²+2a-1=-8+4-1=-5
就是把a+1约分所以a+1≠0a≠-1
当a=-1时A=a²-2a+1=1+2+1=4B=-3a²-4a+2=-3+4+2=3∴3A-B=3*4-3=9
16-2-{-8-[-1-9-(3+6)]}=3再问:还要先化简,在求值再答:16+2a-{8a-[a-9-(3-6a)]}=16+2a-[8a-(a-9-3+6a)]=16+2a-(8a-7a+12
你的题目能清楚点吗,很有歧义再问:已知A=2a²-3a,B=2a²-a-1,当a=-4时,a-b=()比m²-3mn+n²多m²+3mn+n²
当a=1时,a-2a+3a-4a+5a…+99a-100a=1-2+3-4+……+99-100=(-1)×50=-50
loga(a^a+2a-3)应该是loga(a²+2a-3)吧!解析:已知复数z=loga(a²+2a-3)+(a²-3a-10/a+2)i,那么:可知a>0且a≠1且a
3A-B=3(a^2-2a+1)-(-3a-4a+2)=6a^2-2a+1a=-1,3A-B=9
依题意得:a(b2+ab)=-112(1.52+1.5×-112)=0.