a2−2ab b22a−2b÷(1b−1a)=_____
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原式=6a2-4ab-9ab+6b2+4a2-4ab+b2+8a3b6÷83a3b4,=10a2-17ab+7b2+3b2,=10a2-17ab+10b2,=10(a2+b2)-17ab.当a2+b2
a2÷2b,=(1.6×109)2÷(8×103),=(2.56×1018)÷(8×103),=3.2×1014.故选D.
∵3a2+ab-2b2=(3a-2b)(a+b)=0,∴3a-2b=0或a+b=0,解得:a=23b或a=-b,则ab-ba-a2+b2ab=a2−b2−a2−b2ab=−2b2ab=-2ba,当a=
原式=(a+b)(a-b)÷(a+b)+(a-b)2÷(a-b)=(a-b)+(a-b)=2(a-b),当a=12,b=-2时,原式=2×[12-(-2)]=1+4=5.
根号(a2-3a+1)+b2+2b+1=0,则a^2-3a+1=0且b^2+2b+1=0所以a+1/a=3,b=-1a^2+1/a^2=(a+1/a)^2-2=7a^2+1/a^2-绝对值b=6
∵(a+2)2+|a+b+5|=0∴a+2=0a+b+5=0∴a=-2b=-3[(a2+b2)-(a2-b2)+2b(a-b)]÷4b=(a²+b²-a²+b²
2a-3b/b2-a2-a+3b/a2-b2+a+2b/a2-b2=(-2a+3b-a+3b+a+2b)/(a^2-b^2)=(-2a+8b)/(a^2-b^2)=-2(a-4b)/(a^2-b^2)
∵a2+ab-2b2=0,∴(a2-b2)+(ab-b2)=0,∴(a+b)(a-b)+b(a-b)=0,∴(a-b)(a+2b)=0,∴a-b=0或a+2b=0,∴a=b或a=-2b.当a=b时,原
∵a2-3a+1=0,∴a2-3a=-1,a+1a=3,1+a2=3a,∴4a2-9a-2+91+a2,=4(a2-3a)+93a+3a-2,=4×(-1)+3(1a+a)-2,=-4+3×3-2,=
原式可化为a2+4a+4+b2-2b+1=0,即(a+2)2+(b-1)2=0,解得,a=-2,b=1.故a+ba−b=−2+1−2−1=13.故选B.
∵A=4a2+5b,B=-3a2-2b,∴2A-B=2(4a2+5b)-(-3a2-2b)=8a2+10b+3a2+2b=11a2+12b.
a2+b2+a-2b+54=0可化为a2+a+14+b2-2b+1=0,即(a+12)2+(b-1)2=0,于是a=-12,b=1.故a−ba+b=−12−1−12+1=-3.
a²-b²+2b-1=a²-(b²-2b+1)=a²-(b-1)²=(a-b+1)(a+b-1)
(a^2-2ab)/(-ab+b^2)÷a^2/(a-b)÷2ab/(2b-a)=a(a-2b)/[-b(a-b)]÷a^2/(a-b)÷[-2ab/(a-2b)]=a(a-2b)/[b(a-b)]÷
a-b/a+2b÷a2-b2/a2+4ab+4b2-1的值=(a-b)/(a+2b)×(a+2b)²/(a+b)(a-b)-1=(a+2b)/(a+b)-1=(a+2b-a-b)/(a+b)
原式=1-(a-b)/(a+2b)÷(a+b)(a-b)/(a+2b)²=1-(a-b)/(a+2b)×(a+2b)²/(a+b)(a-b)=1-(a+2b)/(a+b)=(a+b
C=(a1+2a2,2a2+3a4,a4+3a1)=(a1,a2,a4)KK=103220031所以40=|C|=|a1,a2,a4||K|=20|a1,a2,a4|所以|a1,a2,a4|=2.|A
(a²-b²)²-2(a²+b²)(a+b)²=[(a-b)(a+b)]²-2(a²+b²)(a+b)
1.|a1+a1,a2-a2|=|2a1,0|=02.A*A+5A-4E=0(A-3E)^2+11A-13E=0(A-3E)^2+11(A-3E)+20E=0(A-3E)[(A-3E)+11E]=-2
将已知条件可以将a、b看做是方程X^2+2X-2=0的两个不同根,那么a+b=-2,ab=-2,后面的式子化简a^2+b^2=(a+b)^2-2ab,这样就很简单了将上面的值代入很容易就算出结果等于-