a-1分之2-a分之1除以a平方-2a 1分之a方加a
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(a-1分之a+1+a的平方-2a+1分之1)除以a-1分之a=[(a+1)/(a-1)+1/(a-1)²]×(a-1)/a=[(a+1)(a-1)/(a-1)²+1/(a-1)&
解[1/(a+1)+1/(a-1)]÷2a/(a²-2a+1)=[(a-1)/(a-1)(a+1)+(a+1)/(a+1)(a-1)]×[(a-1)²/2a]=[(a-1+a+1)
=(3-a²)/(a+1)²+a/(a+1)÷a/(a-1)=(3-a²)/(a+1)²+(a-1)/(a+1)=(3-a²+a²-1)/(
(a-1/a)÷【(a²-2a+1)/a】=【(a²-1)/a】÷【(a-1)²/a】=【(a+1)(a-1)/a】*【a/(a-1)²】=(a+1)/(a-1
{1+4/(a²-4)}÷a/(a-2)=(a²-4+4)/(a²-4))÷a/(a-2)=a²/{(a+2)(a-2)}×(a-2)/a=a/2+2
a+1/a+2=(√a)²+(1/√a)²+2*√a*(1/√a)=(√a+1/√a)²所以原式=√a+1/√a
等于2a再问:你可以把过程写下来照成照片发过来不?再答:再答:可以再答:再答:怎么样再问:没理解到再答:哪里不会再问:没看懂再答:4分之4等于1再答:把括号拆开再答:你题发我看再答:看我会不会列错再问
a∧3-2a∧2+1/a∧4+a∧2-2a+1再问:符号不太清楚再答:你的是整体的平方吗a分之1-a平方是整体的吗是的话a立方-2a平方+1除以a四次方+a方-2a+1再问:不是,是÷a²+
[(a^2+2a分之a-2)-(a^2+4a+4分之a-1)]除以a+2分之a-4,其中a=-3=[(a-2)/a(a+2)-(a-1)/(a+2)²]÷(a-4)/(a+2)=[(a
(2+a-1分之1-a+1分之1)除以(a-1-a平方分之a)=[2+1/(a-1)-1/(a+1)]÷a[1-1/(1-a²)]=[2+1/(a-1)-1/(a+1)]÷a÷[(1-a
结果是b+a分之b-a再问:人
原式=[(a-2)/(a-2)+4/(a-2)]÷a/(a-2)=(a+2)/(a-2)×(a-2)/a=(a+2)/a
原式=(a-1/a)÷[(a-1)^2/a]=[(a^2-1)/a]÷[(a-1)^2/a]=[(a+1)(a-1)/a]/[(a-1)^2/a]=[(a+1)(a-1)]/(a-1)^2=(a+1)
=(a+1)/(a-1)-a/(a-1)²×a=(a+1)(a-1)/(a-1)²-a²/(a-1)²=(a²-1-a²)/(a-1)
1/(a+1)+(a²-a)/(a²-2a-3)÷a/(a-3)=1/(a+1)+(a-1)/(a+1)=a/(a+1)再问:谢谢,我主要是问(a²-2a-3)怎样分解因
(1+a的平方-4分之4)除以a-2分之a=[(a²-4+4)/(a²-4)]÷a/(a-2)=[a²/(a+2)(a-2)]×(a-2)/a=a/(a+2)=(a+2)
[1+3/(a-2)]除以(a+1)/(a^2-4)=(a+1)/(a+2)除以(a+1)/(a+2)(a-2)=(a+1)/(a+2)乘以(a+2)(a-2)/(a+1)=a-2
a分之1除以a=1∕a²a除以a分之1=a²8分之1除以a=1∕8aa分之1除以8=1∕8a