已知圆:x^2 y^2 6x-91=0及P(3,0),求过点P且与已知圆内切
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2/x+2/y=根号24(2y+2x)/xy=2√6x+y=xy√6x/y(x-y)-y/x(x-y)=1/(x-y)[(x/y-y/x)]=1/(x-y)[(x²-y²)/xy]
你的题目有点问题我这样做了x/{y(x-y)}-y/{x(x-y)}=(x平方-y平方)/{xy(x-y)}=(x+y)/xy2/x+2/y=2(x+y)/xy=根号24
令x=cosa则y²=1-cos²a=sin²a所以y=sina所以y-2x=sina-2cosa=√(1²+2²)sin(a-b)=√5sin(a-
先化简[(x²+y²)-(x-y)²+2y(x-y)]/4y[(x²+y²)-(x-y)²+2y(x-y)]/4y=[x²+y&s
(2x-3y)/y=2=>2x-3y=2y=>y=2/5x(1)将(1)式代入待求式子:(x-y)/2x=(x-2/5x)/2x=3/10同理可得(x-3y)/(2x+y)=-1/12
(x+y)/x=11/88x+8y=11y8x=3yy=8x/3(x-y)/(x+2y)=(x-8x/3)/(x+16x/3)=(-5x/3)/(19x/3)=-5/19
∵x2+y2+54=2x+y,∴x2-2x+1+y2-y+14=0,∴(x-1)2+(y-12)2=0,∴x=1,y=12,当x=1,y=12时,原式=1×121+12=13.故答案是13.
原式=(2x-y)(x+y)/(2x-y)^2=(x+y)/(2x-y)x/y=2x=2y原式=3y/3y=1
答:x^2+y^2
你的题是什么意思?“^/”是什么意思?
X+Y分之X-Y等于3x=-2yX+Y分之2(x-y)减X+Y分之3X+Y=(-x-3y)/(x+y)=1
因为(x-y)/(x+y)=3,则(x+y)/(x-y)=1/3则5(x-y)(x+y)-(x+y)/2(x-y)=5*3-1/(3*2)=15-1/6=89/6
X^2表示平方X^2+4X+4+Y^2-2Y+1=0(X+2)^2+(Y-1)^2=0因为平方大于=0所以X+2=0Y-1=0X=-2Y=1X^2+Y^2=5
即(x-2y)²=0x-2y=0所以x=2y所以原式=(2x²+2xy-xy-y²)/(4x²-4xy+y²)=(2x²+xy-y²
4x^2+y^2-4x+10y+26=04x^2-4x+1+y^2+10y+25=0(2x-1)^2+(y+5)^2=0非负数之和为零,所以两个非负数都为零2x-1=0,y+5=0x=1/2,y=-5
1、(x²-10x+25)+(y²-2y+1)=0(x-5)²+(y-1)²=0\所以x-5=0,y-1=0所以x=5,y=12、x²-y²
4x=9yx=9/4*y(1)(x+y)/y=[(9/4)y+y]/y=(9/4+1)y/y=9/4+1=13/4(2)(y-x)/2x=[y-(9/4)y]/[2*(9/4)y]=(1-9/4)y/
最小值0.5,1.5,-1最大值1,1,-1/3约束区域是一个三角形,把三角形的三个顶点代入.可以检验出最大值最小值.
呵呵..诚信的好孩子!我代表全宇宙人民向你致敬!(1)当a>0时0
原式化简=x+2y=2011