已知丨3x-5y-5丨十丨2x-3y-4丨=0,求XY的值

2x-3y-1=0x-2y+2=0∴x=8y=5(3+y²)/(2x-5)是不是3+y²还是3y²=(3+25)/11=28/11

|2-x|+|x-y+4|=02-x=0,x-y+4=0x=2,2-y+4=0,y=63（x-y）-5（x-y）^2-3（x-y）+（y-x）^2+4（x+y）^2+3（y-x）=-4（x-y）^2+

再问：谢谢，再答：不言谢！

[(3x+2y)(3x-2y)-(x+2y)(5x-2y)]/(8x)=[9x²-4y²-(5x²+10xy-2xy-4y²)]/(8x)=(9x²-

[(3x+2y)(3x-2y)-(x+2y)(5x-2y)]÷8x=(9x^2-4y^2-5x^2+2xy-10xy+4y^2)/(8x)=(4x^2-8xy)/(8x)=（x-2y)/2=2012/

y=3x/5原式=x/(x+3x/5)+(3x/5)/[x-3x/5]-(9x^3/25)/(x^3-9x^3/25)=8/3-3/2-9/16=29/48

y=4x/5所以原式=(3x+4x/5)/(x-8x/5)=(19x/5)/(-3x/5)=-19/3

在坐标系中先作2x+5y≥10对应的直线2x+5y=10,取直线上方区域；然后作2x-3y≥-6对应的直线2x-3y=-6,把y的系数变为正,可知取直线下方区域；最后作2x+y≤10对应的直线2x+y

因为(x-y)/(x+y)=3,则(x＋y)/(x－y)＝1/3则5(x-y)(x+y)-(x+y)/2(x-y)＝5*3-1/(3*2)=15-1/6=89/6

2y=x-3带入[(3x+2y)(3x-2y)-(x+2y)(5x-2y)]/4x=[(3x+x-3)(3X-x+3)-(x+x-3)(5x+3-x)]/4x=(8x2-6x=12x-9-8x2=12

X^2表示平方X^2+4X+4+Y^2-2Y+1=0(X+2)^2+(Y-1)^2=0因为平方大于=0所以X+2=0Y-1=0X=-2Y=1X^2+Y^2=5

（x+2）^2+|x+y+5|=0,x+2=0,x+y+5=0x=-2,y=-33(x^2)y-2(x^2)y+2xy-(x^2)y+4x^2-xy=4x^2+xy=4*(-2)^2+(-2)*(-3

原式=(9x²-4y²-5x²-8xy+4y²)÷4x=(4x²-8xy)÷4x=x-2y=2011

1.(-2x^y^)(3x^y^)(-4x^y^)=24x^(1/4-1/2+1/4)y^(-1/3+2/3+2/3)=24x^0y^1=24y2.（6√x)\(3√x√x^5)=18√x^7=18x

3x-2y5=x+y3交叉相乘,乘积相等：5(x+y)=3(3x-2y)5x+5y=9x-6y11y=4x4x=11y那么x：y=11：4

丨3x+y-5丨+丨x-2y-4丨=03x+y-5=01x-2y-4=021式*26x+2y-10=033式+2式7x-14=0x=2y=5-3*2=-1x=2y=-1

X/Y=5/3,求X/(X+Y)+X/(X-Y)-Y^2/(X^2-Y^2)=1/[1+(X/Y)]+1/[1-(X/Y)]-1/[(X^2/Y^2)-1]=1/[1+5/3]+1/[1-5/3]-1

严重怀疑你掉了(x+3)的平方那个2

2x＋y＋3=xy,①若x=1,则y不存在,此时5x＋4y无最值；②若x≠1,则y=(2x＋3)/(x－1),M=5x＋4y=5x＋(8x＋12)/(x－1)=(5x²＋3x＋12)/(x－

原式=x-x+x-x+……-x+(2-1+4-3+5-4+……+2008-2007-2009）y=0+(1×1004-2009)y=-1005y=1005/2