已知x方-3x+1分之x＝2,求x的四次方+x方+1分之x方的值-搜答案-神马作文网

已知x的二次方+3x+1=0,x+3+1/x=0x+1/x=-3(x+1/x)^2=(-3)^2x^2+2+1/x^2=9x^2+1/x^2=7x的平分+x的平方分之一+2x+x分之2=7+2*(-3

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x/(x²-x+1)=33x²-3x+3=x3x²+3=4x平方9x^4+18x²+9=16x²两边减去9x²9(x^4+x²+1

x^2-3x+1=0x^2+1=3x两边除xx+1/x=3平方x^2+2+1/x^2=9x^2+1/x^2=9-2=7

x=1/(2+√3)xy=1y=(2+√3)x=1/(2+√3)x=(2-√3)/(2+√3)(2-√3)x=2-√3(x^2y-xy^2)/(x^2-y^2)=xy(x-y)/(x+y)(x-y)=

∵x+1分之3=3∴x+1=3x=2x的四次方+x方+1=2的四次方+2方+1=16+8+1=25据说方是m³

我操,你这样鬼能看懂啊?分子是啥分母是啥,那些加、除都在什么位置上啊?

X+1/X=2(X+1/X)²=X²+2+(1/X)²=4X²+(1/X)²=2(X²+(1/X)²)²=X^4+2+(

A-B/2=2X^3+3X^2-X-(2X^3+4X^2-X+3)=-X^2-3=-1/4-3=-13/4

2x/(x^2-1)-1/(x+1)=2x/(x^2-1)-(x-1)/(x^2-1)=(2x-x+1)/(x^2-1)=(x+1)/(x^2-1)=1/(x-1)=1/(根号3+1-1)=1/(根号

（x^2+2x+1）/(x^2-3x-4)=(x+1)^2/(x+1)(x-4)=(x+1)/(x-4)

9-61*√5/5

x/(x^2-3x+1)=21/(x-3+1/x)=2x-3+1/x=1/2x+1/x=7/2x^2/(x^4+x^2+1)=1/(x^2+1+1/x^2)=1/[(x+1/x)^2-2+1]=1/[

把每个式子因式分解x的方+5x+4=（x+1）(x+4)x方-5x+6=(x-2)(x-3)………………

x+1/x=3,两边平方得x²+1/x²+2=9即x²+1/x²=7x³+1/x³=(x+1/x)(x²-x×1/x+1/x&su

f(X)等于1+2X二次方分之X二次方f(a)=a²/(1+2a²)

=(x-4)/(x+1)(x-1)除以(x-4)(x+1)/(x+1)平方+1/(x-1)=(x-4)/(x+1)(x-1)乘以(x+1)平方/(x-4)(x+1)+1/(x-1)=(x-4)/(x+

(x-1)/(x^2+3x+2)+6/(2+x-x^2)-(10-x)/(4-x^2)=(x-1)/(x+1)(x+2)-6/(x+1)(x-2)-(x-10)/(x+2)(x-2)=[(x-1)(x

x/(x²+2x+1),(x-1)/(x²+x),1/(x²-1)式1：x/(x+1)²,式2：(x-1)/[x(x+1)],式3：1/[(x+1)(x-1)]

x^2+3x+1=0x^2+1/x^2=((-3x-1)^1+1)/(-3x-1)=(9x^2+6x+2)/(-3x-1)=(-27x-9+6x+2)/(-3x-1)=7x^4+1/x^4=(x^2+