已知x分之1加y分之1等于5-搜答案-神马作文网

分子分母同除以xy,分子变为2（1/x+1/y)+3=2x3+3=9分母变为（1/x+1/y)+2=3+2=5答案是9/5

x^2+y^2+2x-4y+5=0,(x+1)^2+(y-2)^2=0,x=-1,y=2(-1)^2006-1/2=1-1/2=1/2

7/12

再问：2/5再答：？

x/2=y/3=z/4=tx=2ty=3tz=4tx+y-z=1/122t+3t-4t=t=1/12x=1/6y=1/4z=1/3xyz=1/6*1/4/*1/3=1/72

直接设X=1,Y=0.5.带入后式得出10

x+y=6xy=-21/x²+1/y²=(x²+y²)/(x²y²)=[(x+y)²-2xy]/(xy)²=(36+4)

此题简单做法你直接可以设X=1,Y=0.5,使其满足前面的条件即可,带入后面分式,后面的式子中文表述不清,

x（y分之1加z分之1）加y（x分之1加z分之1）加z（x分之1加y分之1）=x(-x分之1)+y(-y分之1)+z(-z分之1)=-1-1-1=-3

x=1/5y=1/7(1/x+1/y)/(1/x-1/y)=(5+7)/(5-7)=12/(-2)=6

由椭圆方程可知,a^2=4,b^2=3,所以c^2=1,所以焦点坐标是（c,0）,（-c,0）,即（-1,0）和（1,0）,焦距=2x^2=1/4y类比x^2=2py焦点坐标(0,1/16),准线方程

原式=[(x+2y)/(x+y)]×[xy/(x+2y)]÷[(x+y)/xy]=[(x+2y)/(x+y)]×[xy/(x+2y)]×[xy/(x+y)]=x²y²(x+2y)/

x/3=y/4=z/5x=3/4y,z=5/4y(x+y-z)/(x-y+z)=(3/4y+y-5/4y)/(3/4y-y+5/4y)=1/2y/y=1/2

3/4x=y/5,则x:y=4:15,y/5=z/6,则y:z=5:6,所以:x:y:z=4:15:18

因为1/x+1/y=-3所以(x+y)/xy=-3即x+y=-3xy所以(x-6xy+y)/(3x+2xy+3y)=(-3xy-6xy)/[3(x+y)+2xy)]=-9xy/(-9xy+2xy)=9

u+v=3,u-v=-1u=1,v=2x=5.5,y=4.5

x/3=y/4=z/5x：Y：Z=3；4;5

1/x+1/y=-1/(x+y)两边同时乘x+y得1+y/x+1+x/y=-1所以y/x+x/y=-3