已知xy=3那么x√(y/x)+y√(x/y)的值为多少?
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/17 16:09:16
(1)因为xy=45(一定),符合反比例的意义,所以x和y成反比例;(2)因为5x=3y,所以x:y=35(一定),符合正比例的意义,所以x和y成正比例;(3)因为知x7=y3,所以x:y=73(一定
5x²-3xy-4y²-11xy-7x²+2y²=5x²-7x²+2y²-4y²-3xy-11xy=-2x²-
xy=6/(x+y)xy(x+y)=6,已知x和y是整数,则xy和(x+y)也是整数,而6=2*3=1*6当xy=3时,x+y=2,无整数解当xy=1时,x+y=6,无整数解当xy=6时,x+y=1,
xy/(x+y)=2∴xy=2(x+y)(3xy-x-y)/(3x-5xy+3y)=[6(x+y)-x-y]/[3x+3y-10(x+y)]=5(x+y)/[-7(x+y)]=-5/7
3xy+4x+2y=3xy+2(2x+y)=3*7+2*8=21+16=37
x-y=3(x-y)²=9x²+y²-2xy=97-2xy=9xy=-1如果满意望采纳!
x+y=3-------(1)xy=1--------(2)将(1)平方得x^2+y^2+2xy=9------(3)将(2)乘以2得2xy=2--------(4)将(3)减去(4)得x的平方加上y
y=1/3x-1所以1/3x^2-2xy+3y^2-2=1/3x^2-2x(1/3x-1)+3(1/3x-1)^2-2=1/3x^2-2/3x^2+2x+1/3x^2-2x+3-2=1
(6x√y/x+3/y*√xy^3)-(4x√x/y+√36xy)=6√(xy)+3√(xy)-4x/y*√(xy)-6√(xy)=(3-4x/y)√(xy)x=3/2,y=27时,原式=(3-2/9
(3x-2y+3xy)-(x-4y-2xy)=3x-2y+3xy-x+4y+2xy=2x+2y+7xy=2(x+y)+5xy=2×3-5×2=-4
你先设x/y=k,即x=yk所以原式=3k^2y^2+ky^2-4y^2=0即y^2(3k^2+k-4)=0因为y不能等于0,所以^2不等于0即3k^2+k-4=0得k=1(x不等于y,舍去),K=-
2(x+xy)-[(xy-3y)-x]-(-xy)=2x+2xy-xy+3y+x+xy=3x+3y+2xy=3(x+y)+2xy=3*(-2)+2*3=0
∵x-y=4xy,∴2x+3xy-2yx-2xy-y=2(x-y)+3xyx-y-2xy=8xy+3xy4xy-2xy=112.故答案为:112.
已知2x+y=4,xy=3,那么2x²y+xy²的值2x²y+xy²=(2x+y)xy =
3x-3y=xy3/x-3/y=1(两边同除xy)1/x-1/y=1/3
还有下面这种方法7x平方-y平方分之x平方-2xy+3y平方分子分母同时除以y²=[(x/y)²-2(x/y)+3]/[7(x/y)²-1]=(4/9-4/3+3)/(2
(x+y)/(x-y)=3/2[(x/y)+1]/[(x/y)-1]=3/23(x/y)-3=2(x/y)+2x/y=5y/x=1/5(x^2+y^2)/xy=x/y+y/x=5+1/5=26/5
①xy同非负时,2x-3√xy-2y=(2√x+√y)(√x-2√y)=0∴√x=2√y,x=4y②xy同负时,2x-3√xy-2y=[2√(-x)+√(-y)][√(-x)-2√(-y)]=0∴√(
x²-4xy+4y²=0(x-2y)²=0则x=2y,因为xy≠0,则x≠0且y≠=0那么(x-y)/(x+y)=(2y-y)/(2y+y)=y/(3y)=1/3