已知x y=8,xy=6,则1.x²y xy²=():2.(x-y)²=()
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题目写错应该是求(6xy+7y)+[8x-(5xy-y+6x)](6xy+7y)+[8x-(5xy-y+6x)]=6xy+7y+8x-5xy+y-6x=xy+2x+8y=xy+2(x+4y)=5+2×
x-xy=8(1)xy-y=-9(2)则有(1)-(2):X-XY-XY+Y=X+Y-2XY=8-(-9)=17
yx+xy=xyx+xyy=xy(x+y)xy,∵x+y=8,xy=6,∴原式=6×86=463.
解题思路:本题是求整式的值,注意一定要先化简,再求值。化简就是先去括号,在合并同类项。解题过程:解:(6xy+7y)+[8x-(5xy-y+6x)]=(6xy+7y)+[8x-5xy+y-6x]=6x
“x愚人国度”您好,很高兴为您解答!x^2y+xy^2=xy(x+y)=-3*6=-18
x^2y+xy^2=xy(x+y)=-3*6=-18
原式=6xy+7y+8x-5xy+y-6x=xy+2x+8y=xy+2(x+4y)=···再问:还有些题哈……
原式=6xy+7y+8x-5xy+y-6x=xy+8y+2x=xy+2(x+4y)=5+2×(-1)=3
6xy+7y)+【8x-(5xy-y+6x)】=xy+8y+2x=xy+2(4y+x)=5-2=3
原式=6xy+7y+8x-5xy+y-6x=xy+2(4y+x)=5-2=3
(6xy+7y)+[8x-(5xy-y+6x)]=6xy+7y+(8x-5xy+y-6x)=6xy+7y+8x-5xy+y-6x=(6xy-5xy)+(7y+y)+(8x-6x)=xy+8y+2x=x
6xy+7y+[8x-5xy+y-6x]=6xy+7y+8x-5xy+y-6x=(6xy-5xy)+(7y+y)+(8x-6x)=xy+8y+2x=xy+2(4y+x)=5-2=3再问:请问x=?y=
因为xy≠0,所以x≠0且y≠0方程两边同时除以y^2得到(x/y)^2-6*x/y+8=0把x/y看成一个整体,这个是关于x/y的一元二次方程(可以换元令t=x/y)可以解得x/y=2或x/y=4
xx+2xy-yy=-3两式相加即可
∵x-y=4xy,∴2x+3xy-2yx-2xy-y=2(x-y)+3xyx-y-2xy=8xy+3xy4xy-2xy=112.故答案为:112.
2x的平方+8xy+9y的平方=2(x的平方+xy)+3(3y的平方+2xy)=2×10+3×6=38再问:是2y的平方,不是的x的再答:那就无解了。肯定是题目出错了再问:我还提了一个问,是一样的,不
∵A=8x²y-6xy²-3xy,B=7xy²-2xy+5x²y ∴C=3(A+B) =3(8x²y-6xy²-3xy+7xy²
那9是负的吗~如果不是等于负1,如果是负九等于十七~用第一个等式减第二个等式
∵5x2-xy-6y2=0,∴(5x-6y)(x+y)=0,∴5x-6y=0,x+y=0,∴5x=6y,x=-y,∴yx=56或-1.故答案为:56或-1.
因为,x-y=3xy所以:-3x+6xy+3y/[(7x-5y)-9xy-(3x-y)]=[-3(x-y)+6xy]/[(7x-5y)-9xy-(3x-y)]=[-3*3xy+6xy]/[7x-5y-