已知 (3m-2n)x2yn 1是关于x,y的5次单项式,求m-2n的值
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根号(11开立方根-根号2)或-根号(11开立方根-根号2)首先根据A=根号n-m+3的m-n次方是n-m+3的算术平方根可以知道m-n=1然后根据B=根号m+2n的m-2n+3次方是m+2n的立方根
A=根号下M+N+3的M+N次方是M+N+3的算术平方根M+N=1/2B=根号下M+2N的M-2N+3次方是M+2N的立方根M-2N+3=1/3求M和N带回去就解就得到答案
易得m=4,n=2所以b-a=-1所以b-a的立方根为-1
解由题意得m-n=2²=4(1)2m-4n+3=3³=9(2)整理m-n=4m-2n=3n=1m=5M=5+3√5-1=5+6=11N=1-2√10-4+3=1-6=-5(M-N)
10m-n+mn=4m*(n+1)=4+nm=(4+n)/(1+n)m和n是正整数所以n=2,m=22m+3n=10
m-n=2m-2n+3=3m=4n=2n-m+3=1m+2n=8A=1,B=2B-A=1
2m+n-3=22m-n+4=3n=3m=1(N-M)^2011=2^2011
∵(5+2)m+(3-25)n+7=(m-2n)5+2m+3n+7=0,∴m-2n=0,且2m+3n+7=0,联立解得:m=-2,n=-1.
x=2m-3n次根号下m+n+3是m+n+3的算术平方根,则2m-3n=2;y=m-n+1次根号下m+2n是m+2n的立方根,则m-n+1=3;可列方程组:2m-3n=2m-n+1=3解方程组,得m=
m-n-1根号下m+3是m+3的算术平方根m-n-1=2m-n=3---(1)2m-4n+3根号下n-2是n-2的立方根2m-4n+3=3m=2n---(2)由(1)(2)得:n=3,m=6M-N=3
A=m-n次根号下m+n+3是m+n+3的算术平方根,B=m-2n+3次根号下m+2n是m+2n的立方根∴m-n=2m-2n+3=3解得m=4,n=2∴A=√﹙M+N+3)=3B=2B-A的立方根=-
因为m+5是m+5的算术平方根,所以(m+5)^2=m+5(m+5)(m+5-1)=0(m+5)(m+4)=0所以m=-5或者-4因为根号n-3是n-3的立方根,所以(n-3)^3=(n-3)^2(n
m+n>=mm+n>=n所以次数为m+n
m+n-5的算术平方根=3则m+n-5=9m-n+4的立方根是-2则m-n+4=-8可知m=1n=13剩下的就很好计算了……
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m-n-1根号下m+3是m+3的算术平方根m-n-1=2m-n=3---(1)2m-4n+3根号下n-2是n-2的立方根2m-4n+3=3m=2n---(2)由(1)(2)得:n=3,m=6m+n=9
m+n-5=9m-n+4=-8m=1n=13m+n-11次根号m-n-1=3次根号-13
m/(m+n)+n/(m-n)-n^2/(m^2-n^2)=[m(m-n)+n(m+n)-n^2]/(m^2-n^2)=m^2/(m^2-n^2)=1/(1-(n/m)^2)=1/(1-(3/2)^2
已知m=5n,则原式=(5n/(5n+n))+(5n/(5n-n))-(n^2)/(((5n)^3)-n^2)=(5/6)+(5/4)-[1/(125n-1)]=(25/12)-[1/(125n-1)
M=(m-n-1)次根号(m+3)是m+3的算术平方根,m-n-1=2N=(2m-4n+3)次根号(n-2)是n-2的立方根,2m-4n+3=3m=6,n=3M=(m-n-1)次根号(m+3)=(6-