9x-3(x-2)=6x 2
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设(x²-1)/(x²+2x)=t则8t+3/t=118t²-11t+3=0(8t-3)(t-1)=0解得t=3/8或t=11.t=3/8(x²-1)/(x
原式=x³-6x²-9x-2x²+12x+18-(x²-5x)(x-3)=x³-8x²+3x+18-(x³-3x²-5x
后面的x²+11x-708有误吧!再问:没有题目就这样能不能帮我再答:那我就试试:原式为:1/x2+x+1/x2+3x+2+1/x2+5x+6+1/x2+7x+12+1/x2+9x+20=5
so easy、、提示一下,望采纳
x^2+3x-2=0,x(x+3)=2,∴(2x-4)╱(x^2+6x+9)÷(x-3)×(x^2-9)╱(2x-x^2)=2(x-2)/(x+3)^*1/(x-3)*(x+3)(x-3)/[x(2-
你可以发个图给个题目吗,这样不知那些是分子,那些是第二项a再问:好吧再问:再答:再答:图中的第二题,你们是一个班的吧?问的问题都一样再问:应该不是再问:第4题就两个步骤?再答:是的再问:最后一步是x-
原式=(x²+3x+9)/(x-3)(x²+3x+9)-6x/x(x-3)(x+3)-(x-1)/2(x+3)=1/(x-3)-6/(x-3)(x+3)-(x-1)/2(x+3)=
原式=[1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)]×(x+4)(x+5)=[1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+1/(x+3)-1/(x
1/(x²+3x+2)=[(x+2)-(x+1)]/(x+1)(x+2)=1/(x+1)-1/(x+2)同理1/(x²+5x+6)=1/(x+2)-1/(x+3)1/(x²
原式可化为1/(x+1)(x-3)+2/(x-3)((x+2)+3/(x+1)(x+2)=0两边同乘以:(x+1)(x+2)(x-3)得:(x+2)+2(x+1)+3(x-3)=0(x≠-1,x≠-2
等式两边同时乘以(x+3)(x-2)(x+2)就可以去分母了
7/(X2+X)+3/(X2-X)=6/(X2-X),去分母,等式两端同时乘X(X+1)(X-1):7(X-1)+3(X+1)=6(X+1),7X-7+3X+3=6X+6,7X+3X-6X=6+7-3
原式=9x+6x2-3x+2x2=8x2+6x,当x=-1时,原式=8×(-1)2+6×(-1)=8-6=2.
(1)4x2-3x=52移项得,4x2-3x-52=0,(x-4)(4x+13)=0,x1=4,x2=-134.(2)5x2=4-2x原方程可化为5x2+2x-4=0,a=5,b=2,c=-4,△=4
1/(x2+x)+1/(x2+3x+2)+1/(x2+5x+6)+1/(x2+7x+12)=1/x(x+1)+1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)=1/x-1/
解方程:x2-6x+2x2-6x=3x2-3x-3-9x=-3x=1/3解不等式:2x3-6x2+4x2-4x≥2x3-2x2+5x-39x-3≤0x≤1/3
x²+x-1/(x²+x)=3/2两边同时乘以(x²+x)得:(x²+x)²-1=3(x²+x)/22(x²+x)²-3
因为X*根号(X^2+3X+18)-X*根号(X^2-6X+18)=1则X*根号(X^2+3X+18)=X*根号(X^2-6X+18)+1两边平方得X^2*(X^2+3X+18)=1+X^2*(X^2
X+3X+9/X-27+6X/9X-X-X-1/6+2X=X-X+3X-X+2X+9/X-27+2/3-1/6=4X+9/X-27+(4-1)/6=4X+9/X-27+1/2=4X+9/X-(54-1
令a=x+1/xa²=x²+2+1/x²2(a²-2)-9a+14=0(2a-5)(a-2)=0x+1/x=5/22x²-5x+2=0(2x-1)(x