7m=2-4n n 5=m
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原式=9-m2+m2-6m-7=-6m+2=-6*1/2+2=-1
原式=4/(m-3)-2(m-3)/(m-3)²=4//(m-3)-2//(m-3)=2//(m-3)=2/(7-3)=1/2
(m+2/m²-2m)-(m-1/m²-4m+4)÷(m-1/m)=(m+2)/m(m-2)-(m-1)/(m-2)^2*m/(m-1)=(m+2)/m(m-2)-m/(m-2)^
2^(2m+6)×2^(3m)÷2^(4m+7)=162^(2m+6+3m-4m-7)=2^42m+6+3m-4m-7=4m=5再问:我第一个式子打错了再答:采纳我,重新问
(m+3m+5m+7m+.+2009m)-(2m+4m+6m+.+2008m)=(1+3+5+7+.+2009)m-(2+4+6+.+2008)m=【(1+2009)×1005÷2-(2+2008)×
(m^3-2m^2+m)/(m^3-m)=(m^2-2m-1)/(m^2-1)=(m-1)^2/(m-1)(m+1)=(m-1)/(m+1)=2010/2012
=(m-2)²/(m+1)(m-1)*(m+1)/m-2+2/m-1=(m-2)/(m-1)+2/m-1=m/m-1=2
原式=(1+2015)m/(2×2)-(2+2014)m/(2×2)=0
原式={[3m(m-2)-m(m+2)]/(m+2)(m-2)}/[2m/(m²-4)]=[(3m²-6m-m²-2m)/(m²-4)]/[2m/(m²
m-2m-3m+4m-5m-6m+7m.2004m=(1-2-3+4-5-6+7-8-9+...2002-2003-2004)m=(-4-7-10-..-2005)m=-(4+7+10+..+2005
前面括号和后面括号里是:各有(1+2009)/2=1005项去掉括号,写成1-2+3-4+5-6.+2009-2010相当于1005个-1相加,最后是-1005
2010m/2=1005m(m+3m+5m+…+2011m)-(2m+4m+6m+…+2010m)=(m+3m+5m+…+2011m)-2m-4m-6m-...-2010m=m-2m+3m-4m+5m
(1m+3m+5m+...+2009m)-(2m+4m+6m+...+2008m)=1m+3m+5m+...+2009m-2m-4m-6m-...-2008m=1m+(3m-2m)+(5m-4m)+.
=(m-2m)+(3m-4m)+.(一共2010/2=1005项)+2011m=-1005m+2011m=1006m
原式=-[(2m+4m+6m+……+2012m)-(m+3m+5m+……+2011m)]=-[(2m-m)+(3m-2m)+……+(2012m-2011m)]=-[m+m+……+m]有2012/2=1
(m2013m)*1007/2-(2m2012m)*1006/2=1007m
=m+(3m-2m)+(5m-4m)+……+(2015m-2014m)=m+1007m=1008m
有规律的,自己仔细看看~
(m)(m)-2m=1两边乘22(m)(m)-4m=2所以2(m)(m)-4m+2008=2+2008=2010